Mary invests £12000 in a savings account.
1 answer:
Answer:
Step-by-step explanation:
We khow that Mary invested 12000£ and the account pays 1.5 percent interest per year.
So we should khow what is the value of this 1.5 percent interst .
12000£⇒100 percent
x ⇒ 1.5 percent
- x=
=180
- mary inested for 2 years so : 2x=2*180=360
so the value after 2 years is : 12000+360=12360
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Answer:
The value of the expression increases as j decreases
Step-by-step explanation:
Let
As j decreases, the value of j300 decreases (i.e the farther j300 is from 150). Due to the wider gap between 150 and j300, the value of f(j) increases.
For example:
When j = 1, f(j) = 150 - (300*1) = -150
When j = 0.5, f(j) = 150 - (300*0.5) = 0
When j = 0. f(j) = 150 - (300*0) = 150
It is obvious from the analogy above that the expression 150-j150−j150 increases as j decreases