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Alex Ar [27]
3 years ago
10

Write the equation in standard form for the circle x^2 + y^2 - 14y + 24 = 0

Mathematics
1 answer:
Vesnalui [34]3 years ago
5 0

Answer:

x^2+(y-7)^2=25

Step-by-step explanation:

x^2+y^2-14y=-24

x^2+(y-7)^2-49=-24

x^2+(y-7)^2=25

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\boxed { \boxed { a_n = a_1 + d(n - 1)}}

a_{14} = -33 , a_{15} = 9,

a_{14} =  a_1 + d(14 - 1) = -33
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\boxed { \boxed { a_n = -578 + 42(n - 1)}}




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