First you need to find the second base (b2) by plugging all the values into the area of a trapezoid formula.
A= 1/2 (b1+b2)h
After plugging it in you will find that b2= 21.3.
The questions is asking perimeter so you add all the sides together...
14.4+18.5+14.7+21.3= 68.9 ft
Hope it helps
For solving of the area of a square pyramid, we can use the formula below:
A=a²+2a sqrt (a²/4 +h²)
where s for the slant height, r for the a/2, where a is the side length and h for the height
Substitute the values,
A=40²+(2*40) SQRT (40²/4 +21²)
A=3920
The answer is 3920 for the area of the square pyramid.
Answer:
intersection is (1,5)
Step-by-step explanation:
plug one equations into the other
y=2x+3
3x+y=8
3x+2x+3=8
simplify
5x+3=8
subtract 3
5x=5
x=1
plug x into one equation
y=2+3=5
intersection is (1,5)
Answer:
True
Step-by-step explanation:
