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abruzzese [7]
2 years ago
6

Kyle bought a ticket to see his favorite basketball team playing at home. His seat is in the terrace section, about 178 feet fro

m the center of the court. If the angle of depression to the court is 59 degrees, which of the following represents the height Kyle is sitting? Round to the nearest tenth.
Mathematics
1 answer:
maw [93]2 years ago
3 0

Answer:

128.6

Step-by-step explanation:

I just did the math

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What is 4 1/6 x 7/8 for my math hw pls help me
SpyIntel [72]

Answer: 3.64583333333

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Dan has some marbles
Andreyy89
A. Frank has 24 marbles. I found this because Dan has 15 and total is 63 so subtract 63-15= 48. 48 divided by 2 people, which are Ellie ans Dan is 24. Dan has 24 marbles.


3 0
3 years ago
HELP IM GIVING 20 POINTS LIKE PLZZ I NEED HELP​
maria [59]

Answer:

price = 4.1

cost = 12.3

Step-by-step explanation:

price = 0.8+1.2+1.5+0.6 = p4.1

cost = 2.40+3.60+4.50+1.80 = $12.3

3 0
2 years ago
A watch cost $75.99. If the sales tax rate is 6.25%, what is the amount of sales tax?
Luden [163]

75.99*0.0625=4.75 hope helps

7 0
3 years ago
businessText message users receive or send an average of 62.7 text messages per day. How many text messages does a text message
KiRa [710]

Answer:

(a) The probability that a text message user receives or sends three messages per hour is 0.2180.

(b) The probability that a text message user receives or sends more than three messages per hour is 0.2667.

Step-by-step explanation:

Let <em>X</em> = number of text messages receive or send in an hour.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em>.

It is provided that users receive or send 62.7 text messages in 24 hours.

Then the average number of text messages received or sent in an hour is: \lambda=\frac{62.7}{24}= 2.6125.

The probability of a random variable can be computed using the formula:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0, 1, 2, 3, ...

(a)

Compute the probability that a text message user receives or sends three messages per hour as follows:

P(X=3)=\frac{e^{-2.6125}(2.6125)^{3}}{3!} =0.21798\approx0.2180

Thus, the probability that a text message user receives or sends three messages per hour is 0.2180.

(b)

Compute the probability that a text message user receives or sends more than three messages per hour as follows:

P (X > 3) = 1 - P (X ≤ 3)

              = 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

             =1-\frac{e^{-2.6125}(2.6125)^{0}}{0!}-\frac{e^{-2.6125}(2.6125)^{1}}{1!}-\frac{e^{-2.6125}(2.6125)^{2}}{2!}-\frac{e^{-2.6125}(2.6125)^{3}}{3!}\\=1-0.0734-0.1916-0.2503-0.2180\\=0.2667

Thus, the probability that a text message user receives or sends more than three messages per hour is 0.2667.

6 0
3 years ago
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