Still not enough information I need numbers or variables
18 is the answer
and i am just typing so i can submit
Assuming that you're talking about a standard deck of 52 cards, there are 4 tens and 4 aces.
So, at the beginning, you have probability 4/52=1/13 to draw a ten.
You replace, and you have an identical probability to draw an ace (you still have 4 favourable cases over 52 total cases).
Multiply the two probabilities to find the answer:

Is the answer..
3, 6, 9, 12, 15, 18, 21, 24, 27, 30 ?
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