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Crank
3 years ago
11

Use a calculator to evaluate cot pi/5

Mathematics
1 answer:
Dovator [93]3 years ago
6 0
It is about <span>1.37638192. 
The cotangent is just one divided by the tangent. So, find the tangent of pi/5 = </span><span>0.726542528, then divide 1 by that number.</span>
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PLEASE HELP IVE ASKED THIS QUESTION 3 TIMES PLEASE HELP!!!!!!!!!!!!!!!!!!!!!!!!​
worty [1.4K]

THEOREM:

  • h² = p² + b² where h is hypotenuse, b is base and p is perpendicular.

ANSWER:

[3] By pythagorean theorem,

  • x² = 14² + 9²
  • x² = 196 + 81
  • x² = 277
  • x = √277
  • x = 16.64 rounded.

[4] By pythagorean theorem,

  • x² = 32² + 24²
  • x² = 1024 + 576
  • x² = 1600
  • x = √1600
  • x = 40.

[5] By pythagorean theorem,

  • (2x)² = 21² – 12.6²
  • 4x² = 441 – 158.76
  • 4x² = 284.24
  • x² = 284.24/4 = 70.56
  • x = √70.56
  • x = 8.4

[6] By tangent property,

  • 7x – 29 = 2x + 16
  • 7x – 2x = 16 + 29
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So, WX = 7(9) – 29 = 63 – 29

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4 0
3 years ago
Tank a has a capacity of 9.5 gallons. 6 1/3 gallons of the tank's water are poured out. how many gallons of water are left in th
Advocard [28]

Answer:

Water left in tank is 3\frac{1}{6} gallons.

Step-by-step explanation:

Given :

Capacity of tank = 9.5 gallons  =\frac{95}{10}

Water taken out of tank =6\frac{1}{3}=\frac{19}{3} gallons

We have to find the water left in the tank.

Water left in the tank = Total capacity of tank - water taken out of tank

                                    =\frac{95}{10}-\frac{19}{3}

Taking LCM of (3,10)= 30

\Rightarrow \frac{95 \times 3-19 \times10}{30}

Solving further, we get,

\Rightarrow \frac{285-190}{30}

\Rightarrow \frac{95}{30}=\frac{19}{6}=3\frac{1}{6}

Thus, Water left in tank is 3\frac{1}{6} gallons..

5 0
3 years ago
Read 2 more answers
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