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almond37 [142]
3 years ago
6

Which of the following represents a true statement?

Mathematics
1 answer:
larisa [96]3 years ago
6 0
<h3>Answer: Statement B in the lower left corner</h3>

When you raise an exponential expression to another exponent, you multiply the exponents. We have 8*5 = 40 as the final exponent. The rule is (x^y)^z = x^(y*z). The base stays the same.

Statement A is not true because we should be adding the exponents. The rule is x^y*x^z = x^(y+z). Note how the bases are all the same. We'll use this rule for statement C to show that it is also false.

A similar rule is (x^y)/(x^z) = x^(y-z). We subtract the exponents this time. This rule is used to show that statement D is false.

You might be interested in
How do you Simplify :(2p^-3)^5
iragen [17]

Answer:

The final simplification is (32p^-15).

Step-by-step explanation:

Given:

(2p^-3)^5 we have to simplify.

Property to be used:(Power rule)

Power rule states that: (a^x)^y=a^x^y ...the exponents were multiplied.

Using power rule.

We have,

⇒(2p^-3)^5          

⇒(2^5)(p^-3^*5)     ...taking exponents individually.

⇒32(p^-^1^5)         ...2^5=2*2*2*2*2=32

⇒32p^-^1^5

So our final values are 32p^-15

3 0
3 years ago
Help would be appreciated :)
RoseWind [281]
Your 3rd option, or (-6,-3,0,3,6) would be the answer
3 0
3 years ago
Question is in photo
Pepsi [2]

Answer:

d

Step-by-step explanation:

because it asks for up to 30

pls brainliest

8 0
2 years ago
Read 2 more answers
X^4 + x^3 + x^2 + x=0
kifflom [539]
X^4 + x^3 + x^2 + x = 0

x(x^3 + x^2 + x + 1) = 0

x[x^2(x + 1) + 1(x + 1)] = 0

x(x + 1)(x^2 + 1) = 0 ⇔ x = 0 or x + 1 = 0 or x^2 + 1 = 0

x = 0 or x = -1 or x^2 = -1 -false

Answer: x= 0 or x = -1.
4 0
3 years ago
PLEASE HELP IVE BEEN STUCK ON THIS ONE FOR QUITE A WHILE.<br>​
Crazy boy [7]

Answer:

I believe it might be C. -3

7 0
2 years ago
Read 2 more answers
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