Answer:$43.29
Step-by-step explanation:
Answer:
In 1981, the Australian humpback whale population was 350
Po = Initial population = 350
rate of increase = 14% annually
P(t) = Po*(1.14)^t
P(t) = 350*(1.14)^t
Where
t = number of years that have passed since 1981
Year 2000
2000 - 1981 = 19 years
P(19) = 350*(1.14)^19
P(19) = 350*12.055
P(19) = 4219.49
P(19) ≈ 4219
Year 2018
2018 - 1981 = 37 years
P(37) = 350*(1.14)^37
P(37) = 350*127.4909
P(37) = 44621.84
P(37) ≈ 44622
There would be about 44622 humpback whales in the year 2018
Answer:
(-∞,∞)
Step-by-step explanation:
It is positive for all x
Answer:
"Vx: if x is a valid argument with true premises then x has a true conclusion"
In a symbol form
Vx ( P(x) ⇒ 2(x) )
Step-by-step explanation:
The Following statement in the form ∀x ______, if _______ then _______ is a valid argument and this because any valid argument with "true premises" has a "true conclusion" as well
we will rewrite this statement in a universal condition statement form
assume x is a valid argument with true premises
then the following holds true
p(x) : x is a valid argument with true premises
q(x) : x has true conclusion
applying universal conditional statement
"Vx, if x is a valid argument with true premises then x has a true conclusion"
In a symbol form
Vx ( P(x) ⇒ 2(x) )
