Lamont lost 8 yards in the first quarter

I need help with this question, I will give brainliest

PolarNik [594]

Answer:

3

Step-by-step explanation:

trust me

5 0

3 years ago

Read 2 more answers

For all values of x, f(x)=2x^2 and g(x)= x+1 Solve fg(x) = gf(x)

Andrej [43]

Answer:

-0.25

Step-by-step explanation:

→ Find fg(x)

2 ( x + 1 )² = 2x² + 4x + 2

→ Find gf(x)

2x² + 1

→ Equate them

2x² + 1 = 2x² + 4x+ 2

→ Move everything to the right hand side

0 = 4x + 1

→ Solve

x = -0.25

4 0

1 year ago

Read 2 more answers

1. Based on the information given, can you determine that the quadrilateral must be a

zhenek [66]

Solving Q1: Given BE = ED and AE = EC.

Considering triangles ΔAED and ΔCEB;

1. AE = EC (given)

2. ∠AED = ∠CEB (vertical angles)

3. ED = EB (given)

ΔAED ≡ ΔCEB (Side-Angle-Side congruency of triangles)

∠DAE = ∠BCE and AD = BC (using CPCTC)

⇒ AD║BC (Converse of Alternate Interior angles theorem)

Similarly consider triangles ΔABE and ΔCDE;

1. AE = CE (given)

2. ∠BEA = ∠DEC (vertical angles)

3. BE = DE (given)

ΔABE ≡ ΔCDE (Side-Angle-Side congruency of triangles)

∠ABE = ∠CDE and AB = CD (using CPCTC)

⇒ AB║CD (Converse of Alternate Interior angles theorem)

Since we have AB║CD, AB = CD and AD║BC, AD = BC.

Therefore, quadrilateral ABCD is a parallelogram.

****************************************************************************************************

Solving Q2: The parallelogram has the angle measures shown in the diagram.

It is clearly visible that both the triangles are Isosceles triangles, so opposite sides in each triangle are equal.

Consider two triangles given in the problem, we have two sets of congruent angles and one included side is common in both triangles.

Using Angle-Side-Angle congruence of triangles, both the triangles would be congruent too.

Using CPCTC, we can say opposite sides of quadrilateral would be congruent.

Therefore, all sides in given quadrilateral are equal.

Hence, Given quadrilateral is a Rhombus.

7 0

2 years ago

An investigator wants to assess whether the mean m = the weight of passengers flying on small planes exceeds the FAA guideline o

stira [4]

Answer:

$H_{0}: \mu= 185$ and $H_{a}: \mu > 185$

Step-by-step explanation:

The null hypothesis $H_{0}$ states that a population parameter (such as the mean, the standard deviation, and so on) is equal to a hypothesized value. We can write the null hypothesis in the form $H_{0}: parameter = value$

In this context, the investigator's null hypothesis should be that the average total weight is no different than the reported value by the FAA. We can write it in this form $H_{0}: \mu= 185$ .

The alternative hypothesis $H_{a}$ states that a population parameter is smaller, greater, or different than the hypothesized value in the null hypothesis. We can write the alternative hypothesis in one of three forms

$H_{a}: parameter > value\\H_{a}: parameter < value\\H_{a}: parameter \neq value$

The investigator wants to know if the average weight of passengers flying on small planes exceeds the FAA guideline of the average total weight of 185 pounds. He should use $H_{a}: \mu > 185$ as his alternative hypothesis.

7 0

3 years ago

If x varies directly with y and x = 2.5 when y = 10, funny x when y = 16.

amid [387]

Answer:

Should be 4.0(Not sure tho. my thought process is complicated but to me it makes sense)

Step-by-step explanation:

If y=10 and x =2.5, if y were to = 20, then x would equal 5. so you take that ratio, and say 6 is 3/5's the way to 10, so you also divide 2.5 by 3/5

you get 1.5, you add that to x already and you get 4.0

so if y=16, x should =4.0

3 0

3 years ago

Lamont lost 8 yards in the first quarter​

Lamont lost 8 yards in the first quarter