4x^4-2x^3y-3xy^3-9y^4

Mathematics

1 answer:

schepotkina [342]3 years ago

8 0

4x^4 - 3xy^3 -9y^4 -2x^3y

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How to do this step by step?

serg [7]

The answer is 27.6
angle version of the law of cosines:

cos(C) = (a^2 + b^2 − c^2)/2ab

cos(A) = (b^2 + c^2 − a^2)/2bc

cos(B) = (c^2 + a^2 − b^2)/2ca

cos A = (b^2 + c^2 − a^2) / 2bc
cos A = (10^2+20^2-14^2)/200
cos A = (100+400-196)/200
cos A = (500-196)/200
cos A = (304)/200
cos A = (1.52)
A = cos^-1(1.52) = 40.54 degrees

cos B = (c^2+a^2-b^2)/2ca
cos B = (20^2+14^2-10^2)/280
cos B = (400+196-100)/280
cos B = (496)/280
cos B ≈ 1.77
B = cos^-1(1.77) = 27.66 degrees

we have two methods left to find the measure of angle C:
method 1 :
cos C = (a^2+b^2-c^2)/2ab
cos C = (14^2+10^2-20^2)/140
cos C = (196+100-400)/140
cos C = (-104)/140
cos C ≈ -0.74

C = cos^-1(-0.74) = 111.8 degrees

method 2: 40.54+27.66 = 68.2
180-68.2=111.8

The measure of angle A: 40.54
The measure of angle B: 27.66
The measure of angle C: 111.8

6 0

4 years ago

A set of 10 cards consists of five red cards and five black cards. The cards are shuffled thoroughly, and I choose one at random

Kamila [148]

Answer:

The mean of X is 2

Step-by-step explanation:

Given the data in the question;

set of 10 cards consist of 5 red card and 5 blacks

cards are chosen, replaced and shuffled four times;

number of independent trials n = 4

now, since its is replaced, the probability of getting a red card in each trial will be;

p = 5/10 = 0.5

let X rep the number of red cards observed in the four trials.

the random variable follows binomial distribution where

n = 4 and p = 0.5

E(X) = ∑xP( X = x )

E(X) = np

we substitute

E(X) = 4 × 0.5

E(X) = 2

Therefore, The mean of X is 2

6 0

3 years ago

Graphing a line given its slope and y-intercept

kifflom [539]

Answer:

see below for a graph

Step-by-step explanation:

One point can be plotted at the y-intercept: (0, -2). Since the slope tells you the line drops 3 units for each 2 units to the right, the point (2, -5) will be another point on the line. The graph will go through those two points.