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alexira [117]
3 years ago
11

An equation that represents the path of a diver jumping off a diving board is y = –7x2 + 5x + 16. Graph this function from the p

oint where the diver jumped to the point where they reach the water.

Mathematics
1 answer:
ANTONII [103]3 years ago
7 0

Answer:

See explanation

Step-by-step explanation:

An equation that represents the path of a diver jumping off a diving board is

y = -7x^2 + 5x + 16.

The diver jumped to the water when x = 0.

Then

y=-7\cdot 0^2+5\cdot 0+16=16

The jumper reached the water when y = 0, then

-7x^2+5x+16=0\\ \\D=5^2-4\cdot (-7)\cdot 16=25+448=473\\ \\x_{1,2}=\dfrac{-5\pm\sqrt{473}}{-14}

So, point where the  jumper reached the water is

\left(\dfrac{5+\sqrt{473}}{14},0\right)\approx (1.93,0)

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