Question

An equation that represents the path of a diver jumping off a diving board is y = –7x2 + 5x + 16. Graph this function from the point where the diver jumped to the point where they reach the water.

Answer 1

Answer:

See explanation

Step-by-step explanation:

An equation that represents the path of a diver jumping off a diving board is

$y = -7x^2 + 5x + 16.$

The diver jumped to the water when x = 0.

Then

$y=-7\cdot 0^2+5\cdot 0+16=16$

The jumper reached the water when y = 0, then

$-7x^2+5x+16=0\\ \\D=5^2-4\cdot (-7)\cdot 16=25+448=473\\ \\x_{1,2}=\dfrac{-5\pm\sqrt{473}}{-14}$

So, point where the  jumper reached the water is

$\left(\dfrac{5+\sqrt{473}}{14},0\right)\approx (1.93,0)$