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3 years ago

Write the equation of the line.

Mathematics

2 answers:

zepelin [54]3 years ago

5 0

Answer:

1/3x - 2 i think

Step-by-step explanation:

Oksana_A [137]3 years ago

4 0

Y = 1/3x - 2.
If you sub in 0, you’ll get (0, -2) which is the y intercept.

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Solve 0= 2t^3-21t^2+ 40t

sukhopar [10]

$0=2t^3-21^2+40t$
switch sides
$2t^3-21t^2+40t=0$
solve factoring
$t(t-8)(2t-5)=0$
using the zero factor principle
$t=0
$
solve
$t-8=0:t=8$
solve
$2t-5=0:t= \frac{5}{2}$
$t=0,t=8,t= \frac{5}{2}$
Hope this helps

4 0

3 years ago

Which of the following is an extraneous solution of the square root of -3x-2=x+2

yarga [219]

Answer:

x=-6 is an extraneous solution

Step-by-step explanation:

we have

$\sqrt{-3x-2} =x+2$

squared both sides

$-3x-2=(x+2)^2$

$-3x-2=x^2+4x+4$

$x^2+7x+6=0$

solve the quadratic equation by graphing

The solution is x=-6 and x=-1

see the attached figure

<u><em>Verify each solution</em></u>

substitute the value of x in the original expression

For x=-6

$\sqrt{-3(-6)-2} =-6+2$

$\sqrt{16} =-4$

$4=-4$ ----> is not true

Is an extraneous solution

For x=-1

$\sqrt{-3(-1)-2} =-1+2$

$\sqrt{1} =1$

$1=1$ ----> is true

Is the solution

4 0

3 years ago

Find the maxmium area of a rectangular plot of land which can be enclosed by rope of length 60 metres

mario62 [17]

Answer:

225 m²

Step-by-step explanation:

If W is the width of the rectangle, and L is the length, then:

60 = 2W + 2L

A = WL

Use the first equation to solve for one of the variables:

30 = W + L

L = 30 − W

Substitute into the second equation:

A = W (30 − W)

A = 30W − W²

This is a parabola, so we can find the vertex using the formula x = -b/(2a).

W = -30 / (2 × -1)

W = 15

Or, we can use calculus:

dA/dW = 30 − 2W

0 = 30 − 2W

W = 15

Solving for L:

L = 30 − W

L = 15

So the maximum area is:

A = WL

A = (15)(15)

A = 225

3 0

3 years ago

Based on the polynomial remainder theorem, what is the value of the function when x=−6 ?

Vaselesa [24]

ANSWER

$f( - 6) = 10$

EXPLANATION

The given function is
$f(x) = {x}^{4} + 8 {x}^{3} + 10 {x}^{2} - 7x + 40$

According to the remainder theorem,

$f( - 6) = R$
where R is the remainder when
$f(x)$

is divided by
$x + 6$

We therefore substitute the value of x and evaluate to obtain,

$f( - 6) = { (- 6)}^{4} + 8 {( - 6)}^{3} + 10 { (- 6)}^{2} - 7( - 6)+ 40$

$f( - 6) = 1296 + 8 ( - 216) + 10 (36) - 7( - 6)+ 40$

$f( - 6) = 1296 - 1728 + 360 + 42+ 40$

This will evaluate to,

$f( - 6) = 10$

Hence the value of the function when
$x = - 6$

is
$10$

According to the remainder theorem,
$10$
is the remainder when

$f(x) = {x}^{4} + 8 {x}^{3} + 10 {x}^{2} - 7x + 40$
is divided by
$x + 6$

3 0

3 years ago

7 (8.02) need answer asap

timama [110]

Both groups are similar.

7 0

3 years ago