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Brums [2.3K]
3 years ago
13

Which explains how to find the quotient of the division below? Negative 3 and one-third divided by StartFraction 4 over 9 EndFra

ction Write Negative 3 and one-third as Negative StartFraction 13 over 3 EndFraction, and find the reciprocal of StartFraction 4 over 9 EndFraction as StartFraction 9 over 4 EndFraction. Then, rewrite Negative 3 and one-third divided by StartFraction 4 over 9 EndFraction as Negative StartFraction 13 over 3 EndFraction times StartFraction 9 over 4 EndFraction. The quotient is Negative 9 and three-fourths. Write Negative 3 and one-third as Negative StartFraction 10 over 3 EndFraction, and find the reciprocal of StartFraction 4 over 9 EndFraction as StartFraction 9 over 4 EndFraction. Then, rewrite Negative 3 and one-third divided by StartFraction 4 over 9 EndFraction as Negative StartFraction 10 over 3 EndFraction times StartFraction 9 over 4 EndFraction. The quotient is Negative 7 and StartFraction 6 over 12 EndFraction = Negative 7 and one-half. Write Negative 3 and one-third as Negative StartFraction 9 over 3 EndFraction. Then, rewrite Negative 3 and one-third divided by StartFraction 4 over 9 EndFraction as Negative StartFraction 9 over 3 EndFraction times StartFraction 4 over 9 EndFraction. The quotient is Negative 1 and one-third. Write Negative 3 and one-third as Negative StartFraction 10 over 3 EndFraction. Then, rewrite Negative 3 and one-third divided by StartFraction 4 over 9 EndFraction as Negative StartFraction 10 over 3 EndFraction times StartFraction 4 over 9 EndFraction. The quotient is Negative 1 and StartFraction 13 over 27 EndFraction = Negative 1 and StartFraction 13 over 27 EndFraction.
Mathematics
3 answers:
Ulleksa [173]3 years ago
4 0

Answer:

(B) Write Negative 3 and one-third as Negative StartFraction 10 over 3 EndFraction, and find the reciprocal of StartFraction 4 over 9 EndFraction as StartFraction 9 over 4 EndFraction. Then, rewrite Negative 3 and one-third divided by StartFraction 4 over 9 EndFraction as Negative StartFraction 10 over 3 EndFraction times StartFraction 9 over 4 EndFraction. The quotient is Negative 7 and StartFraction 6 over 12 EndFraction = Negative 7 and one-half.

Step-by-step explanation:

To find the quotient of the division:

-3\dfrac13 \div \dfrac49

Step 1: \text{Write}$ $ -3\dfrac13$ as $ -\dfrac{10}{3}

-3\dfrac13 \div \dfrac49 =  -\dfrac{10}{3} \div \dfrac49

Step 2: Find the reciprocal of  \dfrac94

-\dfrac{10}{3} \times \dfrac94\\=-7\dfrac12

Assoli18 [71]3 years ago
4 0

Answer:

b

Step-by-step explanation:

Lina_smartkid2 years ago
0 0

-10 isyour answer

Lina_smartkid
2 years ago
is*
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compering by fraction 2 1/2 = 5/2
2/5
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3 years ago
Read 2 more answers
What are the coordinates of the point that is one half the distance between A(-1, -2) and B(6, 12)?
MA_775_DIABLO [31]

The coordinates of the point that is one-half the distance between A(-1,-2) and B(6,12) is (2.5,5)

What is the midpoint?

The mid-point lies midway between the two ends. Its x value lies in the middle of the other two x values. Its y value lies in the middle of the other two y values.

Given, A(6,12) = (x_{1}, y_{1} )

           B(6,12) = (x_{2}, y_{2} )

Let M is a midpoint of AB, then

M(x,y)=(\frac{x_{1}+x_{2}  }{2} ,\frac{y_{1} +y_{2}}{2} )= (\frac{-1+6}{2} ,\frac{-2+12}{2} )=(2.5,5)

The midpoint of point AB is M(2.5,5)

Therefore, the coordinates of the point which is one-half the distance between A(-1,-2) and B(6,12) is M(2.5,5).

To learn more about the midpoint

brainly.com/question/24676143

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5 0
1 year ago
Can someone help me plz
galben [10]

Step-by-step explanation:

the answer is in the image above

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3 years ago
Given: (↔AB) ║ (↔CD)
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2 years ago
The formula of the area of the triangle is A=1/2bh solve for h
inn [45]

Answer:

Answer:

h = \frac{2A}{b}

Step-by-step explanation:

Given

A = \frac{1}{2} bh

Multiply both sides by 2 to clear the fraction

2A = bh ( isolate h by dividing both sides by b )

h = \frac{2A}{b}

4 0
3 years ago
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