It’s would be 28 well at least that what my calculation say.
First take the derivative of the Y w.r.t t
so
dy/dt =50(-1) (1 + 6e^(-2t))^(-2) . (6e^(-2t) . (-2)
=600 e^(-2t) / (1 + 6e^(-2t))^2
to find that where it is maximum we take the drivative again
d²y/dt² = 600 e^(-2t) . (-2) . (1 + 6e^(-2t))^(-2) + 600 e^(-2t) . (-2) (1 + 6e^(-2t))^(-3) . (-12 e^(-2t)) = [-1200 e^(-2t) (1 + 6e^(-2t)) + 1200 e^(-2t) . 12e^(-2t)] / (1 + 6e^(-2t))^3 = 1200 e^(-2t) [6e^(-2t) - 1] / (1 + 6e^(-2t))^3 which will be 0 when 6e^(-2t) = 1, so e^(-2t) = 1/6 => -2t = ln (1/6) = -ln 6 => t = (1/2) ln 6
for value of y we know that
6e^(-2t) = 1, so y = 50 / (1 + 6e^(-2t)) = 50 / (1 + 1) = 25. So the coordinates are ((ln 6) / 2, 25).
Answer: She did not use the factors in correct order therefore she is inncorrects
Step-by-step explanation: I got it right on edge
Answer: x = -1 and y = 5
Step-by-step explanation:
7x + 3y = 8 ........................... equation 1
4x - y = - 9 ............................ equation 2
Solving the simultaneous linear equation by substitution method , make y the subject of the formula from equation 2 , we have
y = 4x + 9 ............................. equation 3
substitute y = 4x + 9 into equation 1 , we have;
7x + 3 ( 4x + 9 ) = 8
7x + 12x + 27 = 8
19x + 27 = 8
subtract 27 from both sides
19x = -19
divide through by 19
x = -1
substitute x = -1 into equation 3 , we have
y = 4 ( -1) + 9
y = -4 + 9
y = 5
Therefore :
x = -1 and y = 5
