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NNADVOKAT [17]
3 years ago
5

Find the slope of the line.

Mathematics
2 answers:
scoundrel [369]3 years ago
7 0
The points we can clearly see are (-2,-2) and (0,-3). You have to rise up 2 points and got to the left 4, so the rise over run is 2 over -4. Simplify this to -1/2, so the slope is negative 1/2.
Dovator [93]3 years ago
7 0

Answer:

The slope of the line is -\frac{1}{2}

Step-by-step explanation:

To know the slope of a line we can have the equation or to know points of the line. In this case from the graph we can get to points (-4,-1) and (0,-3). Having this and using the equation to calculate the slope, we have:

m=\frac{y2-y1}{x2-x1}

Defining:

(x1=-4,y1=-1) and (x2=0,y2=-3)

Replacing this values in the initial equation, this is:

m=\frac{-3-(-1)}{0-(-4)}

m=\frac{-2}{4} =-\frac{1}{2}

The slope of the line is -\frac{1}{2}

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Simplify the expression to a polynomial in standard form: (4x-3)(-2x^2-7x-5)
Brums [2.3K]

How to solve your problem

(4−3)(−22−7−5)

(4x−3)(−2x2−7x−5)(4x-3)(-2x^{2}-7x-5)(4x−3)(−2x2−7x−5)

Simplify

1

Distribute

(4−3)(−22−7−5)

(4x−3)(−2x2−7x−5){\color{#c92786}{(4x-3)(-2x^{2}-7x-5)}}(4x−3)(−2x2−7x−5)

4(−22−7−5)−3(−22−7−5)

2

distribute

4(−22−7−5)−3(−22−7−5)

4x(−2x2−7x−5)−3(−2x2−7x−5){\color{#c92786}{4x(-2x^{2}-7x-5)}}-3(-2x^{2}-7x-5)4x(−2x2−7x−5)−3(−2x2−7x−5)

−83−282−20−3(−22−7−5)

3

−83−282−20−3(−22−7−5)

−8x3−28x2−20x−3(−2x2−7x−5)-8x^{3}-28x^{2}-20x{\color{#c92786}{-3(-2x^{2}-7x-5)}}−8x3−28x2−20x−3(−2x2−7x−5)

−83−282−20+62+21+15

4

Solution

−83−222++15

I know this looks like a lot but its just how you solve your problem.

therefor, your answer is

Solution

−83−222++15

<em>Hope this helps!</em>

<em>Have a great day!</em>

<em>-Hailey</em>

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