3 years ago

A system of equations is shown below.

1 answer:

4 0

Multiply equation B by 3 and add the result to

equation A.

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zimovet [89]

Answer:

$f^{-1}(x)=\sqrt[3]{x}-1$

Step-by-step explanation:

$f(x)=(x+1)^3\\\\y=(x+1)^3\\\\x=(y+1)^3\\\\\sqrt[3]{x}=y+1\\\\y=\sqrt[3]{x}-1\\ \\f^{-1}(x)=\sqrt[3]{x}-1$

Graphing both inverses, they will be symmetrical about the line $y=x$ .

8 0

3 years ago

Ad libitum [116K]

Well the P should probably be 4

7 0

3 years ago

alexira [117]

The solution is 4x+2x=6x then 6x+10=solution

4 0

3 years ago

ohaa [14]

Answer: (-5,35)

Step-by-step explanation:

-7x=-5x+10

Get x on one side by adding 5x

-2x=10

Simplify by dividing by -2

X=-5

Substitute into y=-7x

Y=-7(-5)

Simplify

Y=35

5 0

3 years ago

alexira [117]

This is even because they all can be divided if it was odd you would not be able to decide them

5 0

3 years ago