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jonny [76]
3 years ago
5

Match function with its corresponding graph

Mathematics
1 answer:
MrMuchimi3 years ago
3 0

Answer:

Step-by-step explanation:

We can see that there are roots at (-2,0) and (-1,0)

also, the root at (-2,0) should bounce right off

and the root at (-1,0) should go through

With all that being said it has to be B

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Evaluate b^2 for b= -4
tekilochka [14]

Answer:

16

Step-by-step explanation:

b^2

Let b= -4

(-4)^2

16

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3 years ago
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222+203 is it compatible or rounding
snow_lady [41]
I belive it is rounding
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Is 6-6 and 1-6 equal
uranmaximum [27]

Answer:

no

Step-by-step explanation:

6-6=0

1-6=-5

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3 years ago
Choose all the quadratic pairs that are equivalent. 1 2 (x + 4)2 = 2 x2 + 8x + 15 = 0 (x − 5)2 = 1 x2 − 10x + 26 = 0 3(x − 1)2 +
Artemon [7]

Answer:

Only equation 1 and 2 are equal.

Step-by-step explanation:

2 (x + 4)2 = 2

2( x² + 8x+ 16) = 2               Applying the square formula

2x² + 16x+ 32 = 2

2x² + 16x+ 32 -2= 0

2x² + 16x+ 30 = 0

2( x² + 8x+ 15)= 0           Taking 2 as common

x2 + 8x + 15 = 0------------eq 1

x2 + 8x + 15 = 0-------------eq 2

(x − 5)2 = 1

x²-10x+25= 1             Applying the square formula

x²-10x+25- 1= 0

x²-10x+24= 0-------------eq 3

x2 − 10x + 26 = 0 -------------eq 4

3(x − 1)2 + 5 = 0

3( x²-2x+1)+5= 0               Applying the square formula

3x²-6x+3+5= 0

3x²-6x+ 8= 0-------------eq 5

3x2 − 6x + 8 =1

3x2 − 6x + 8 -1=0

3x2 − 6x + 7 =0-------------eq 6

3 0
2 years ago
What are the vertical asymptote(s) of y= (x-6)/(x+8) (x-7)
White raven [17]

Answer:

x = -8 and x= 7

Step-by-step explanation:

recall that for a rational expression, the vertical asymptotes occur at x-values that causes the expression to become undefined. These occur when the denominator becomes zero.

Hence the asymptototes will occur in x-locations where the denominator , i.e

(x+8)(x-7) = 0

solving this, we get

(x+8) = 0 ----> x = -8

or

(x-7) = 0 ------> x = 7

hence the asymptotes occur x = -8 and x= 7

5 0
2 years ago
Read 2 more answers
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