find y=mx+b for line parallel to AB.
The line that is parallel will have the same slope as line AB:
the slope of line AB is
m=(8-3)/(-10-2)
=5/-12
=-5/12
Since the line going through X is parallel the vertical distance of the new line to AB is the same for all values of the domain(x-axis).
at x=-5 the point X has the y value of 10 which is 4 more than the y value for AB based on the graph.
To find the intercept b of the line going through X that is parallel to AB we just add 4 to the intercept of AB, which is 4 so
4+4=8
That would be 8, its in the center so forget 9 or 7.
Answer:
Last option?
Step-by-step explanation:
ax+by=c
4x+6y=60
a=4
b=6
c=60
You'll want to use the quadratic formula:
-b (+/-) sqrt(b^2 - 4ac), all divided by 2a.
Under the square root you'll get:
-11
remember that the square root of -1 is i.
sqrt(-11) can be factored to sqrt(11*-1) and then sqrt(-1) * sqrt(11)
which becomes i*sqrt(11)
so your complex solution is:
-3 (+/-) (i*sqrt(11)), all over 4
