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3 years ago

A set of equations is given below:

Mathematics

2 answers:

Gemiola [76]3 years ago

5 0

2d+1=3d+5.
If both equations equal c, then both equations can be equal to each other.

katovenus [111]3 years ago

4 0

Answer:

The correct option is 1.

Step-by-step explanation:

The given set of equations is

Equation A: c = 2d + 1

Equation B: c = 3d + 5

Using equation A and equation B, equate the value of c.

$2d+1=3d+5$

$1-5=3d-2d$

$-4=d$

The value of d is -4. So the value of c is

$c=2d+1=2(-4)+1=-7$

The equation 2d+1=3d+5 is used to find the solution to the set of equations, therefore the correct option is 1.

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310 tickets were sold in advance before school pay and 340 door tickets were sold in advance.

Step-by-step explanation:

Given:

Let number of tickets sold in advance be 'x'.

Cost of advance ticket = $3

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Also given:

Thirty more tickets were sold at door in advance

Hence number of door tickets sold = $x+30$

Total Money Collected = $2630

Now we can say that Total Money Collected is equal to sum of number of tickets sold in advance multiplied by Cost of advance ticket and number of door tickets sold multiplied by Cost of door tickets.

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Solving the equation to find the value of x we get;

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$\frac{8x}{8} =\frac{2480}{8}\\ \\x=310$

Substituting the value of x to find number of door tickets been sold.

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Hence, 310 tickets were sold in advance before school pay and 340 door tickets were sold in advance.

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