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Galina-37 [17]
4 years ago
7

I need help, please

Mathematics
1 answer:
Advocard [28]4 years ago
8 0

Answer:

The equation for h in terms of V,r and π is 3V/πr².

Step-by-step explanation:

Given:

The formula for the volume of a cone is V=\frac{1}{3}\pi r^{2}h.

Now, for solving the equation we put the formula of cone,

V=\frac{1}{3}\pi r^{2}h.

Multiplying both sides with 3 we get :

3V=\pi r^{2}h

Then, dividing both sides by π we get:

\frac{3V}{\pi}=r^{2}h.

And, dividing both sides by r² we get:

\frac{3V}{\pi r^{2} }=h.

Therefore, the equation for h in terms of V,r and π is 3V/πr².

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PICK ME!!
asambeis [7]

Answer:

Well, as it turns out, when two figures are similar or congruent, they have certain properties, and these properties can be used to prove relationships between the figures. When two figures are similar figures, they have the following properties: Corresponding angles have equal measure.

Step-by-step explanation:

6 0
4 years ago
What number is 120% of 70
kaheart [24]

70/x=100/120
(70/x)*x=(100/120)*x       - we multiply both sides of the equation by x
70=0.833333333333*x       - we divide both sides of the equation by (0.833333333333) to get x
70/0.833333333333=x
84=x
x=84

now we have:
<span>120% of 70=84</span>
8 0
4 years ago
125 cm to 87.4 cm percent of change
netineya [11]

Answer:

% Change = (87.5 - 125) / 125 * 100%

= -37.5 / 125 * 100%

= -0.3 * 100%

= -30 %

The percent change is -30 % or 30% decrease.

4 0
3 years ago
What should you know about the slopes of perpendicular lines? SOMEONE HELP ME
Goryan [66]

Let's use an example

Say we had two lines P and Q. If P has slope 2/5, then Q must have slope -5/2 in order for P and Q to be perpendicular.

Note how -5/2 is the negative reciprocal of 2/5. In other words, you flip the fraction and the sign to go from either slope.

Another thing to notice is that the two slopes multiply to -1. This is true for any pair of perpendicular lines as long as neither line is vertical.

8 0
4 years ago
Read 2 more answers
What is the mass of a 350 cm cubed sample of pure silicon with a density of 2.336 g/cm cubed?
olganol [36]
D = m
----
v

2.336 g/cm^3 = m
----
350
(350) 2.336 = m

817.6g = m


5 0
3 years ago
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