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Marina86 [1]
3 years ago
14

How do you simplify this with no negative exponents ? (2x^-2 y^3) (3x^3 y^3)

Mathematics
1 answer:
mafiozo [28]3 years ago
8 0

Answer:

6xy with the power of 6

You might be interested in
38. At night, a driver should dim his headlights when an oncoming vehicle comes within:
White raven [17]

Answer:

500 feet because D and B is too close and C is in the middle. I would go with A.

8 0
3 years ago
Complete the square x^2-10=16<br><br>​
Hatshy [7]

Answer:

(x - 5)² = 41

Step-by-step explanation:

* Lets revise the completing square form

- the form x² ± bx + c is a completing square if it can be put in the form

 (x ± h)² , where b = 2h and c = h²

# The completing square is x² ± bx + c = (x ± h)²

# Remember c must be positive because it is = h²

* Lets use this form to solve the problem

∵ x² - 10x = 16

- Lets equate 2h by -10

∵ 2h = -10 ⇒ divide both sides by 2

∴ h = -5

∴ h² = (-5)² = 25

∵ c = h²

∴ c = 25

- The completing square is x² - 10x + 25

∵ The equation is x² - 10x = 16

- We will add 25 and subtract 25 to the equation to make the

 completing square without change the terms of the equation

∴ x² - 10x + 25 - 25 = 16

∴ (x² - 10x + 25) - 25 = 16 ⇒ add 25 to both sides

∴ (x² - 10x + 25) = 41

* Use the rule of the completing square above

- Let (x² - 10x + 25) = (x - 5)²

∴ (x - 5)² = 41

3 0
3 years ago
The domain of ​(f​g)(x) consists of the numbers x that are in the domains of both f and g.
Dovator [93]

The statement "The domain of (fg)(x) consists of the numbers x that are in the domains of both f and g" is FALSE.

Domain is the values of x in the function represented by y=f(x), for which y exists.

THe given statement is "The domain of (fg)(x) consists of the numbers x that are in the domains of both f and g".

Now we assume the g(x)=x+2 and f(x)=\frac{1}{x-6}

So here since g(x) is a polynomial function so it exists for all real x.

f(x)=\frac{1}{x-6}<em>  </em>does not exists when x=6, so the domain of f(x) is given by all real x except 6.

Now,

(fg)(x)=f(g(x))=f(x+2)=\frac{1}{(x+2)-6}=\frac{1}{x-4}

So now (fg)(x) does not exists when x=4, the domain of (fg)(x) consists of all real value of x except 4.

But domain of both f(x) and g(x) consists of the value x=4.

Hence the statement is not TRUE universarily.

Thus the given statement about the composition of function is FALSE.

Learn more about Domain here -

brainly.com/question/2264373

#SPJ10

3 0
2 years ago
I need all please help
RUDIKE [14]

Answer:

5) D

6) C

7) B

8) D

9) 109°

10) 83°

Step-by-step explanation:

5) In y=mx+b the slope is m. In perpendicular it'll be opposite, so the answer is D.

6) With the above knowledge about slope, the slope will be the same so it'll be C.

7) They are in the same position by different lines and will be corresponding aka B

8) These are adjacent angles because they are next to each other aka D

9) 180 - 71 = 109

10) They are correspodning so 83°

(slightly rushing so I hope this helped, have a nice day!)

6 0
3 years ago
If x &lt;.-4 what must be true?
lesantik [10]

Answer:

x{-5,-6,-7.....,-infinity} so no.c)x is to the left of -4 on number line

Hope it helps

8 0
3 years ago
Read 2 more answers
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