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2 years ago

5

: Kevin is planting 15 bushes and 9 trees in rows. If he wants all the rows to be exactly the same, with no plants left over, wh

at is the greatest number of rows Kevin can plant? You can use a factor tree or list the factors to help you

2 answers:

kicyunya [14]2 years ago

6 0

Answer:

There will be 5 rows of bushes.

There will be 3 rows of trees.

Step-by-step explanation:

Kevin is planting 15 bushes and 9 trees in rows.

He wants all the rows to be exactly the same, with no plants left over.

So, the greatest number of rows Kevin can plant will be given by finding the GCF of 15 and 9.

15 = 3 x 5

9 = 3 x 3

GCF = 3

There will be $15/3=5$ rows of bushes.

There will be $9/3=3$ rows of trees.

Flauer [41]2 years ago

5 0

Answer:

The greatest number of rows that can be planted, and have nothing left over, would be 3

Step-by-step explanation:

Find the greatest common factor (gcf) of 15 and 9

15: 1 3 5 15

9: 1 3 9

In this case, the gcf of 15 and 9 would be 3.

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3 years ago

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2 years ago

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3 years ago

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2 years ago

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Vinil7 [7]

Answer:

The factors of $2(x+y)^2-9(x+y)-5$ is ((x+y)-5)(2x+2y+1)

Step-by-step explanation:

Given polynomial

=> $2(x+y)^2-9(x+y)-5$

To Find:

The factors of the polynomial =?

Solution:

Lets assume k = (x+y)

Then $2(x+y)^2-9(x+y)-5$ can be written as $2k^2-9k-5$

Now by using quadratic formula

k = $\frac{-b\pm\sqrt{(b^2-4ac}}{2a}$

where

a= 2

b= -9

c= -5

Substituting the values, we get

k = $\frac{-b\pm\sqrt{(b^2-4ac)}}{2a}$

k = $\frac{-(-9) \pm \sqrt{((-9)^2-4(2)(-5)}}{2(2))}$

k = $\frac{-(-9) \pm \sqrt{(81+40)}}{4}$

k = $\frac{-(-9) \pm \sqrt{(121)}}{4}$

k = $\frac{-(-9) \pm 11}}{4}$

k= $\frac{ 9 \pm 11}{4}$

k = $\frac{20}{4}$ k = $\frac{-2}{4}$

$k_1 =5$ $k_2 = -\frac{1}{2}$

$2k^2-9k-5= 2(k-5)(k+\frac{1}{2})$

Solving the RHS we get

$\frac{2}{2}(k-5)(2k+1)$

$(k-5)(2k+1)$

Substituting k = x+y

$((x+y)-5)(2(x+y+1)$

$((x+y)-5)(2x+2y+1)$

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2 years ago