Answer:
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Solve the Function Operation
Use the given functions to set up and simplify
140
.
350
m
e
t
e
r
s
=
350
m
t
e
2
r
s
140
=
350
m
t
e
2
r
s
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Find the Exact Value
The chosen topic is not meant for use with this type of problem. Try the examples below.
csc
(
60
)
sin
(
330
)
cos
(
390
)
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Identify the Sequence
Use the formula
a
n
=
a
1
+
d
(
n
−
1
)
to identify the arithmetic sequence.
a
n
=
700
m
t
e
2
r
s
+
140
n
−
140
−
350
m
t
e
2
r
s
n
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Simplify
Simplify the expression.
157.68432
m
4
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Simplify the expression.
157.68432
m
4
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Simplify the expression.
157.68432
m
4
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How was this solution?
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Not the answer you were looking for?
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Solve the Function Operation
Simplify
0.9
⋅
(
0.2
m
)
⋅
(
6.9
m
)
⋅
(
13.8
m
)
⋅
(
9.2
m
)
.
157.68432
m
4
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Simplify
0.9
⋅
(
0.2
m
)
⋅
(
6.9
m
)
⋅
(
13.8
m
)
⋅
(
9.2
m
)
.
157.68432
m
4
Answer:
1/5
Step-by-step explanation:
It is easy to see a right triangle on each side of the original square with its hypotenuse on the side of the original square, each with an area of 2⋅A2=A. Thus the total area of the original square is 5A, or the ratio of the area of the shaded square to the original square is 1/5.
Your answer is -8.8..................
Question;
Assumption:
Let us assume Brandon's running speed is = 18.30 and
Ruben's running speed is = 16.50 and
Answer:
The two equations that can represent the relationship between the meters and second for Brandon and Ruben are;
Brandon → Y₁ = 18.3·X₁ and
Ruben → Y₂ = 16.5·X₂
Step-by-step explanation:
The equation is of the form
Y = 17.45·X
That is Amy ran Y meters in X seconds
Therefore we have
or the value 17.45 is the running speed of Amy
Therefore, where the running speed of Brandon is 18.30 and the running speed of Ruben is 16.50 we have
Y meters ran by Brandon in X seconds given by
Y₁ = 18.3·X₁ and
For Ruben we have Y meters ran in X seconds given by
Y₂ = 16.5·X₂.
Answer:
Step-by-step explanation:
I think this is just adding so 450+5+455,you can also use a calculator on questions like these.
