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4 years ago

PLZZ HELPP FAST WILL GIVE MEDAL!!

Mathematics

1 answer:

Afina-wow [57]4 years ago

6 0

8 5 8 5 hopefully its right i'm not good at this kind of stiff

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Find the average rate of change of f(x)=2x^2-7x from x=2 to x=5

m_a_m_a [10]

Answer:

Step-by-step explanation:

The average rate of change of f(x) in the close interval [ a, b ] is

$\frac{f(b)-f(a)}{b-a}$

Here [ a, b ] = [2, 5 ]

f(b) = f(5) = 2(5)² - 7(5) = 50 - 35 = 15

f(a) = f(2) = 2(2)² - 7(2) = 8 - 14 = - 6, thus

average rate of change = $\frac{15-(-6)}{5-2}$ = $\frac{21}{3}$ = 7

3 0

3 years ago

Jason and Maria are playing a board game in which three dice are tossed to determine a player's move. Find each probability for:

fredd [130]

Tossing a die will have 6 possible outcomes. Those are having sides that are number 1 to 6. The sample space of tossing 3 dice is equal to 6³ which is equal to 216. Now for the calculation of probabilities,

P(two 5s) = (1 x 1 x 5)/216
As we have to have the 5 in the die for two times, then for the 1 time, we can have all other numbers except 5. The answer is 5/216.

P(three 5s) = (1 x 1 x 1)/216 = 1/216

P(one 5 or two 5s) = (1 x 5 x 5)/216 + (1 x 1 x 5)/216 = 5/36

6 0

3 years ago

What is the mixed number form of 33/8

goblinko [34]

HCF of 8 that will go as much as possible to 33

4*8=32 and denominator is 8

33-32=1 which is the numerator

Answer is :

4 1/8

4 0

3 years ago

Read 2 more answers

A soft drink filling machine, when in perfect adjustment, fills the bottles with 12 ounces of soft drink. A random sample of 49

grandymaker [24]

Answer:

yes

Step-by-step explanation:

4 0

3 years ago

A college entrance exam company determined that a score of 24 on the mathematics portion of the exam suggests that a student is

seraphim [82]

Answer:

a) The Z -value 2.397 < 2.576 at 99% or 0.01% level of significance

Null hypothesis is accepted at 0.01% level of significance

They score is above 24 on the math portion of the exam

b)

Null Hypothesis: There is no significance difference between the college level mathematics and math courses in high school

H₀: μ = 24

Alternative Hypothesis: H₁: μ ≠ 24

Step-by-step explanation:

Step(i):-

Given random sample 'n' = 250

Given data sample mean x⁻ = 24.5

Standard deviation = 3.3

Null Hypothesis: There is no significance difference between the college level mathematics and math courses in high school

H₀: μ = 24

Alternative Hypothesis: H₁: μ ≠ 24

test statistic

$Z = \frac{x^{-} - mean}{\frac{S.D}{\sqrt{n} } }$

$Z = \frac{24.5 - 24}{\frac{3.3}{\sqrt{250} } } = \frac{0.5}{0.2087} = 2.397$

a) 99% or 0.01% level of significance

Level of significance ∝ = 0.01

$Z_{\frac{\alpha }{2} } = Z_{\frac{0.01}{2} } = Z_{0.005} =2.576$

The Z -value 2.397 < 2.576 at 99% or 0.01% level of significance

Null hypothesis is accepted at 0.01% level of significance

They score is above 24 on the math portion of the exam

b) 95% or 0.05% level of significance

Level of significance ∝ = 0.05

$Z_{\frac{\alpha }{2} } = Z_{\frac{0.05}{2} } = Z_{0.025} = 1.96$

The Z -value 2.397 > 1.96 at 95% or 0.05% level of significance

Null hypothesis is Rejected at 0.05% level of significance

They score is below 24 on the math portion of the exam

6 0

3 years ago