Step-by-step explanation:
I got you,
a) Work...
First equation: y = 4x + 3
Second equation: y = 2x + 11
If he wants to play 2 games...
y = 4 (2) + 3
y = 11
y = 2 (2) + 11
y = 15
<u>Answer for part a: If a customer wants to rent shoes and play two games, they'll pay more with the new price plan. With the current price plan, they'll pay 11 dollars, but with the new price plan, they'll pay 15 dollars.</u>
b) Work...
seven games...
y = 4 (7) + 3
y = 31
y = 2 (7) + 11
y = 25
<u>Answer for part b: If the customer wants to play 7 games, including the shoes, they would pay less using the new plan. If the shes were not included, the new price will still be less. With the shoes, 7 games, with the original plan, is 31 dollars but 25 dollars with the new plan. If they didn't want to rent shoes, they would pay 28 dollars with the original plan but only 14 dollars with the new plan. All in all, they spend less on the new plan anyways.</u>
I hope this helps :)
Answer:
a. 8 gallons
b. (11-0.75t) gallons
Step-by-step explanation:
a. Here in this question, we are told that the total amount of fuel in the fuel tank is 11 gallons and the car consumes 0.75 gallon per hour. We are interested in knowing the amount of fuel left in the tank after driving for four hours.
We proceed as follows;
Since 0.75 gallon is consumed in an hour, the amount of fuel consumed in 4 hours would be the amount consumed in an hour * 4 hours
Mathematically, that would be 0.75 * 4 = 3 gallon
Now, the amount of fuel left is simply the difference between the initial amount of fuel in the tank minus the amount of fuel present after 4 hours.
That would be; 11 - 3 = 8 gallons
b. Like above, we want to know the amount of fuel left after t hours.
Since 0.75 is used up per hour, the amount used up in t hours would be 0.75 * t = 0.75t
Now, the amount of fuel that would be left in the tank would be the difference between what we had initially and what was used up.
Mathematically, that would be 11- 0.75t
The volume of a sphere is defined as:
V=(4*pi*r^3)/3
then, if we double the radius of the sphere (r=2r):
V=(4*pi*(2r)^3)/3
V=(4*pi*(2^3*r^3))/3
V=(4*pi*r^3)/3*8
Then, the answer is that if you double the radius of the sphere, its volume is increased 8 times.
The answer to the question
