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3 years ago

What's the answer? Just checking mine. 40 - 2 x 3^2

Mathematics

2 answers:

WITCHER [35]3 years ago

6 0

Answer:

Step-by-step explanation:

Order of Operations: BPEMDAS

Step 1: Write out expression

40 - 2 × 3²

Step 2: Exponents

40 - 2 × 9

Step 3: Multiply

40 - 18

Step 4: Subtract

Snowcat [4.5K]3 years ago

6 0

Steps to solve:

40 - 2 * 3^2

~Solve the exponent

40 - 2 * 9

~Multiply

40 - 18

~Subtract

Best of Luck!

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2 years ago

Pleasantburg has a population growth model of P(t)=at2+bt+P0 where P0 is the initial population. Suppose that the future populat

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The population will reach 34,200 in February of 2146.

Step-by-step explanation:

Population in t years after 2012 is given by:

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Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

In this question:

$0.8t^{2} + 6t - 15200 = 0$

So $a = 0.8, b = 6, c = -15200$

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$t_{2} = \frac{-6 - \sqrt{48356}}{2*0.8} = -141.64$

We only take the positive value.

134 years after 2012.

.14 of an year is 0.14*365 = 51.1. The 51st day of a year happens in February.

So the population will reach 34,200 in February of 2146.

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