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harina [27]
3 years ago
10

Find the domain and the range of the function g(x)=5(x+1)^2+4

Mathematics
1 answer:
igomit [66]3 years ago
8 0
Try this explanation:
this is quadratic function (parabola, common view of equation is y=ax²+bx+c).
Domain: The function exists in all the points. It means, that x∈R or x∈(-oo;+oo).
Range: according to the common view a>0, it means, that parabola has 'min' in its vertice (x₀=-1). Range is y∈[4;+oo) or y≥4.

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Answer:

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B2-4b+4=0 using quadratic forumla
Ivan

Trying to factor by splitting the middle term   

Factoring <span> b2-4b+4</span> 
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<span><span>     </span></span>

<span><span>-4   +   -1   =   -5</span><span>     -2   +   -2   =   -4   That's it</span></span>


Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -2  and  -2 
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Step-4 : Add up the first 2 terms, pulling out like factors :
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