All categories

3 years ago

A Line Segment has the points (1,-2), and (3,-2). What are the new points after its dilated by a scale factor of 3/2 or 1.5

Mathematics

1 answer:

jeka57 [31]3 years ago

5 0

Answer:

The new points after dilation are

(3/2, -3) and (9/2,-3)

Step-by-step explanation:

Here in this question, we want to give the new points of the line segment after it is dilated by a particular scale factor.

What is needed to be done here is to multiply the coordinates of the given line segment by the given scale factor.

Let’s call the positions on the line segment A and B.

Thus we have;

A = (1,-2) and B = (3,-2)

So by dilation, we multiply each of the specific data points by the scale factor and so we have;

A’ = (3/2, -3) and B’= (9/2,-3)

You might be interested in

When using ANOVA, the sum of squares within is: Group of answer choices Showing the difference between the groups Effect varianc

prohojiy [21]

Answer:

When using ANOVA, the sum of squares within is: Showing the difference between the Total SS and Between SS known as Error variance

Step-by-step explanation:

Within SS is also known as Error sum of squares . It is calculated by finding the difference between Total Sum of Squares and Between Sum of Squares

with the given degrees of freedom.

Within SS = Total SS - Between SS

Where

Total SS= ∑∑X²- C. F

Between SS= ∑T²j/r - C.F

Correction Factor = CF = Tj²/n

So the correct answer would be

Showing the difference between the Total SS and Between SS also known as Error variance.

8 0

3 years ago

A snail is moving along a path that is 4 meters long. The snail moves at an average rate of 3 3/10 inches per minute. Question 1

Troyanec [42]

Answer: The length of the path = 157 inches { approx}

Step-by-step explanation:

Given: The length of the path = 4 meters

1 meter = 100 centimeters

So 4 meters = 400 centimeters

Also 1 in. ≈ 2.54 cm

$\Rightarrow\ 1 cm = \dfrac{1}{2.54}\ in.$

Now, $\text{ 400 centimeters}=400\times\dfrac{1}{2.54}\text{ inches}$

$=157.480314961\approx 157 \ \ \ \ \ \text{ [Rounded to the nearest inch.]}$

Hence, the length of the path = 157 inches { approx}

5 0

3 years ago

Solve for x In the triangle

Goryan [66]

$\boxed {\boxed { \sin(\theta) = \dfrac{\text{opp}}{\text{hyp}} }}$

$\sin(38 \textdegree) = \dfrac{x}{11}$

$x = 11 \times \sin(38 \textdegree)$

$x = 6.8 \text { units}$

8 0

3 years ago

Write the polynomial in standard form. Then name the polynomial based on its degree and number of terms.

sattari [20]

Let A= <span>2 – 11x2 – 8x + 6x2, the standard form of A is
A = - 5x² -8x + 2

</span>

7 0

3 years ago

Read 2 more answers

An object at the top of a building with height 110 feet is thrown upward with an initial speed of 23 ft/s. Find its position z(t

alina1380 [7]

Answer:

Step-by-step explanation:

Given

Height of building is $h=110\ ft$

Initial upward velocity $u=23\ ft/s$

height of object is given by

$z(t)=ut+\frac{1}{2}gt^2$

but building is already at a height of 110 ft so z(t) must be given by

$Z(t)=ut+\frac{1}{2}(-g)t^2+110$

$Z(t)=23\times t-\frac{1}{2}\times 9.8\times t^2$

$Z(t)=-16t^2+23t+110$

Time when it hits is given by when Z(t)=0[/tex]

$-16t^2+23t+110=0$

$t=\frac{-23\pm \sqrt{(23)^2-4\times (-16)\times 110}}{2\times (-16)}$

$t=\frac{-23\pm 87}{-32}$

$t=3.43\ s$

6 0

4 years ago