We model the ticket as a rectangle.
For this case what you should know is that the perimeter of the rectangle is given by:
P = 2w + 2l
The area of the rectangle is given by:
A = w * l
In both cases:
w: width
l: long
We have the following system of equations:
32 = 2w + 2l
60 = w * l
Solving the system we obtain:
The dimensions of the ticket are:
(10 cm) * (6 cm)
Answer: the dimensions of the ticket are: (10 cm) * (6 cm) Note: see attached image for system solution
Whenever you add or subtract fractions you have to have the denominators the same so that the numerator is of the same value system.
For example you have 8/16 - 8/32
If you were you to subtract it without changing denominators to the same it would be equal to zero but when you change them to the same denominator
16/32 - 8/32 then the answer would be 8/32.
Answer:
B: x=-5 and x=4
Step-by-step explanation:
f(x)= x^2 + x -20
To find the zeros we replace f(x) with 0

now we solve for x
LEts factor x^2 + x -20
sum is +1 and product is -20
5 * (-4)= -20
5 + (-4) = +1
x^2 + 5x - 4x - 20 = 0
(x^2 + 5x)+(- 4x - 20) = 0
x(x+5) -4 (x+5) = 0
(x-4)(x+5)=0
Set each factor =0 and solve for x
x- 4 =0 so x=4
x+5 =0 so x=-5
x=-5 and x=4
Answer:
p = 35
Step-by-step explanation:

I hope I helped you^_^
1 1/3 = 4/3 (because (3 * 1 + 1) / 3)
We need both parts of sum to have common denominator.
Second part have denominator = 6.
When we multiply nominator and denominator of first part by 2 we get 8/6 (what is legit operation on fractions)
Now easily add:
8/6 + (- 5/6) = 8/6 - 5/6 = 3/6 (here we can divide both nominator and denominator by 3 to get "nicer" result) = 1/2