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2 years ago

Use your knowledge about parentheses and substitution to solve the following:

Mathematics

2 answers:

meriva2 years ago

5 0

Answer:

16. r(s)(t) =

r=2, s=3, t=4

(2)(3)(4)=

(2*3) = 6 ---> 6(4) = 24

final: 24

17. (r)(s)(t)(x)(y) =

r = 2, s = 3, t = 4, x = 5, y = 6

(2)(3)(4)(5)(6)

2*3=6

6*4=24

24*5= 120

120*6=720

final: 720

18. (7x + 2Y) =

x = 5, y = 6

rewrite---> = [7(5) + 2(6)]

[35 + 12] = 47

final: 47

hope this helpsss sorry took a while LOL

Step-by-step explanation:

q = 1; r = 2; s = 3; t = 4; x = 5; y = 6

AleksAgata [21]2 years ago

3 0

Answers:

7. 2(5 + 4) + 10 =
2 x 9 + 10
18 + 10
= 28

8. 3(6(5)) + 4 =
3 x 30 + 4
90 + 4
= 94

9. 10(5)(6) =
50 x 6
= 300

10. 5(5 + 6) =
5 x 11
= 55

11. 2(2)(3) + 4(5) =
12 + 4 x 5
12 + 20
= 32

12. 2(1) + 2(5 + 4) =
2 + 2(5 + 4)
2 + 2 x 9
2 + 18
= 20

13. 6(7(4) + 4(3)) =
6(28 + 4 x 3)
6(28 + 12)
6 x 40
= 240

14. 9(10(5)) + 10(6) =
9 x 50 + 10 x 6
9 x 50 + 60
450 + 60
= 510

15. 2(5)(5(6)) =
2 x 5 x 30
= 300

16. 2(3)(4) =
6 x 4
= 24

17. (2)(3)(4)(5)(6) =
10 x 3 x 4 x 6
30 x 4 x 6
120 x 6
= 720

18. (7(5) + 2(6)) =
35 + 2 x 6
35 + 12
= 47

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Which justification describes the process?

tester [92]

Answer:

Option 1 - Using the Subtraction Property of Equality, 2 is subtracted from both sides of the equation.

Step-by-step explanation:

Given : Process

Step 1: 4x + 2 = 10

Step 2: 4x = 8

To find : Which justification describes the process?

Solution :

From step 1 to step 2, we subtract 2 both sides

Step 1: 4x + 2 = 10

Subtracting 2 both side,

⇒ 4x + 2-2 = 10-2

Step 2: 4x = 8

So, The best justification is 'Using the Subtraction Property of Equality, 2 is subtracted from both sides of the equation'.

Therefore, Option 1 is correct.

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3 years ago

Read 2 more answers

Find the numbers b such that the average value of f(x) = 7 + 10x − 9x2 on the interval [0, b] is equal to 8.

barxatty [35]

Answer:

The numbers $b$ such that the average value of $f(x) = 7 +10\cdot x - 9\cdot x^{2}$ on the interval [0, b] is equal to 8 are $b_{1} \approx 1.434$ and $b_{2} \approx 0.232$ .

Step-by-step explanation:

The mean value of function within a given interval is given by the following integral:

$\bar f = \frac{1}{b-a}\cdot \int\limits^b_a {f(x)} \, dx$

If $f(x) = 7 +10\cdot x - 9\cdot x^{2}$ , $a = 0$ , $b = b$ and $\bar f = 8$ , then:

$\frac{1}{b}\cdot \int\limits^b_0 {7+10\cdot x -9\cdot x^{2}} \, dx = 8$

$\frac{7}{b}\int\limits^b_0 \, dx + \frac{10}{b} \int\limits^b_0 {x}\, dx - \frac{9}{b} \int\limits^b_0 {x^{2}}\, dx = 8$

$\left(\frac{7}{b} \right)\cdot b + \left(\frac{10}{b} \right)\cdot \left(\frac{b^{2}}{2} \right)-\left(\frac{9}{b} \right)\cdot \left(\frac{b^{3}}{3} \right) = 8$

$7 + 5\cdot b - 3\cdot b^{2} = 8$

$3\cdot b^{2}-5\cdot b +1 = 0$

The roots of this polynomial are determined by the Quadratic Formula:

$b_{1} \approx 1.434$ and $b_{2} \approx 0.232$ .

The numbers $b$ such that the average value of $f(x) = 7 +10\cdot x - 9\cdot x^{2}$ on the interval [0, b] is equal to 8 are $b_{1} \approx 1.434$ and $b_{2} \approx 0.232$ .

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Step-by-step explanation:

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3 years ago

"The manager for State Bank and Trust has recently examined the credit card account balances for the customers of her bank and f

yuradex [85]

Answer:

$P(X = 4 ) = 0.1876$

$P(X \le 4) = 0.8358$

Step-by-step explanation:

From the question we are told that

The proportion that has outstanding balance is p = 0.20

The sample size is n = 15

Given that the properties of the binomial distribution apply, for a randomly selected number(X) of credit card

$X \ \ ~ Bin (n , p )$

Generally the probability of finding 4 customers in a sample of 15 who have "maxed out" their credit cards is mathematically represented as

$P(X = 4 ) = ^nC_4 * p^4 * (1 - p)^{n-4}$

=> $P(X = 4 ) = ^{15}C_4 * (0.20)^4 * (1 - 0.20)^{15-4}$

Here C stand for combination

=> $P(X = 4 ) = 0.1876$

Generally the probability that 4 or fewer customers in the sample will have balances at the limit of the credit card is mathematically represented as

$P(X \le 4) = [ ^{15}C_0 * (0.20)^0 * (1 - 0.20)^{15-0}]+[ ^{15}C_1 * (0.20)^1 * (1 - 0.20)^{15-1}]+\cdots+[ ^{15}C_4 * (0.20)^4 * (1 - 0.20)^{15-4}]$

=> $P(X \le 4) = 0.8358$

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3 years ago