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laila [671]
4 years ago
11

Can someone please help me with this question? and show work! PLEASE HELP!!!

Mathematics
1 answer:
Goshia [24]4 years ago
3 0

You don’t need help if you have a calculator you can’t do it by your self I’ll explain though.

The shipping cost —— per pound. Multiply 11 and add it from what the bag cost

And do that to all of the possible answers and which ever one is the smallest amount even by a cent

Is the answer. I will add a visual explanation

50$ for the bag and plus shipping 0.89 cents per pound

0.89 multiplied by 11 = 9$ and 79 cents. Add that by 50. 59$ and 79 cents

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A rectangle has an area of 45x2 − 42x − 48 and a width of 5x − 8. What is the length of the rectangle? To find the length of the
hichkok12 [17]

Answer:

The length of the rectangle is given as:

(9x + 6)

Step-by-step explanation:

The area of a rectangle is given as:

Length × Width

Area of the rectangle = 45x² − 42x − 48

Width = 5x - 8

We solve for the length of the rectangle by factorising the area of the rectangle

45x² − 42x − 48

45x² - 72x + 30x - 48

(45x² - 72x )+ (30x - 48)

9x(5x - 8) + 6(5x - 8)

(5x - 8)(9x + 6)

Therefore:

The length of the rectangle is given as:

(9x + 6)

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2880 / 112 = 25.71 square inches per hr
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If QS bisects PQT, SQT=(8x- 25),PQT=(9x+34), and SQR=112, find each measure.
Goryan [66]

The values of the angles are; x = 12°, m∠PQS = 71°, m∠PQT = 142° and m∠TQR = 41°

<h3>What are the measure of the each angle?</h3>

The required angles; x, m∠PQS, m∠PQT, and m∠TQR

The given parameters are bisects ∠PQT

m∠SQT = (8·x - 25)°

m∠PQT = (9·x + 34)°

m∠SQR = 112°

We have;

m∠PQT = m∠SQT + m∠PQS (Angle addition postulate)

m∠SQT ≅ m∠PQS (Angles formed by angle bisector are congruent)

m∠SQT = m∠PQS  by Definition of congruency

m∠PQT = 2 × m∠SQT

Therefore;

(9·x + 34)° = 2 × (8·x - 25)° = (16·x - 50)°

Collecting like terms gives:

(34 + 50)° = 16·x - 9·x = 7·x

7·x = 84°

x = 84°/7 = 12°

x = 12°

m∠SQT = (8·x - 25)°

Therefore;

m∠SQT = (8 × 12 - 25)° = 71°

m∠SQT = 71°

m∠PQT = 2 × m∠SQT

∴ m∠PQT = 2 × 71° = 142°

m∠PQT = 142°

m∠PQS = m∠SQT (Angles formed by the same bisector )

∴ m∠PQS = m∠SQT = 71°

m∠PQS = 71°

m∠SQR = m∠SQT + m∠TQR (Angle addition postulate)

m∠SQT = 71°

∴  m∠SQR = 112° = 71° + m∠TQR

m∠TQR = 112° - 71° = 41°

m∠TQR = 41°

Learn more about angles here:

brainly.com/question/2882938

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Answer:

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B.

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$6.78/pound*10pounds=$67.80
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