Answer: The required derivative is 
Step-by-step explanation:
Since we have given that
![y=\ln[x(2x+3)^2]](https://tex.z-dn.net/?f=y%3D%5Cln%5Bx%282x%2B3%29%5E2%5D)
Differentiating log function w.r.t. x, we get that
![\dfrac{dy}{dx}=\dfrac{1}{[x(2x+3)^2]}\times [x'(2x+3)^2+(2x+3)^2'x]\\\\\dfrac{dy}{dx}=\dfrac{1}{[x(2x+3)^2]}\times [(2x+3)^2+2x(2x+3)]\\\\\dfrac{dy}{dx}=\dfrac{4x^2+9+12x+4x^2+6x}{x(2x+3)^2}\\\\\dfrac{dy}{dx}=\dfrac{8x^2+18x+9}{x(2x+3)^2}](https://tex.z-dn.net/?f=%5Cdfrac%7Bdy%7D%7Bdx%7D%3D%5Cdfrac%7B1%7D%7B%5Bx%282x%2B3%29%5E2%5D%7D%5Ctimes%20%5Bx%27%282x%2B3%29%5E2%2B%282x%2B3%29%5E2%27x%5D%5C%5C%5C%5C%5Cdfrac%7Bdy%7D%7Bdx%7D%3D%5Cdfrac%7B1%7D%7B%5Bx%282x%2B3%29%5E2%5D%7D%5Ctimes%20%5B%282x%2B3%29%5E2%2B2x%282x%2B3%29%5D%5C%5C%5C%5C%5Cdfrac%7Bdy%7D%7Bdx%7D%3D%5Cdfrac%7B4x%5E2%2B9%2B12x%2B4x%5E2%2B6x%7D%7Bx%282x%2B3%29%5E2%7D%5C%5C%5C%5C%5Cdfrac%7Bdy%7D%7Bdx%7D%3D%5Cdfrac%7B8x%5E2%2B18x%2B9%7D%7Bx%282x%2B3%29%5E2%7D)
Hence, the required derivative is
Answer:
T<7
Step-by-step explanation:
21+7T+8<43
29+7T<43
7T<43‒29
7T<14
7T/7<14/7
T<7
i think it is clear &i hope it helps you
Answer:
Step-by-step explanation:
6f^2 - 9f + 10 + 2f^2 + f - 3
8f^2 - 8f + 7
TheProfessor35's answer is correct, but here's a step by step as you asked. PEMDAS stands from Parentheses Exponents Multiplication Division Addition Subtraction. So, in the problem, you first solve the part inside the parentheses. Are there exponents? No, so we move on. Anything need to be multiplied? Yes, 20.3 x 0.7. That gives us 14.21. Now, there is nothing left in the parentheses to be divided, added, or subtracted, so we move on to the outside. We multiply 14.21 by 7 and get 99.47.
HIS walking rate was 1 mile per hour because 20min times 3 is 1 hour, and 1/3 times 3 is 1 mile thus 1mph if can plz mark brainliest
