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Fittoniya [83]
3 years ago
9

A teacher gave a benchmark test to see how well her students were prepared for an

Mathematics
1 answer:
WARRIOR [948]3 years ago
6 0

Answer:

rcfnjcndcndc

Step-by-step explanation:

d

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Will mark as brainlist
lara [203]

Step-by-step explanation:

Tn=ar^(n-1)

r=-10/-5=2

a=-5

Tn=-5×(2)^(n-1)

Tn=-5•(2)^(n-1)

an=5•(2)^(n-1)

7 0
2 years ago
Where does the last one go???
Nostrana [21]

Answer:

is goes to ¨¨not a function¨¨

Step-by-step explanation:

8 0
3 years ago
f of x equals 4 x over quantity x squared minus 16. Show all work to identify the asymptotes and zero of the function.
yuradex [85]

Given:

The function is

f(x)=\dfrac{4x}{x^2-16}

To find:

The asymptotes and zero of the function.

Solution:

We have,

f(x)=\dfrac{4x}{x^2-16}

For zeroes, f(x)=0.

\dfrac{4x}{x^2-16}=0

4x=0

x=0

Therefore, zero of the function is 0.

For vertical asymptote equate the denominator of the function equal to 0.

x^2-16=0

x^2=16

Taking square root on both sides, we get

x=\pm \sqrt{16}

x=\pm 4

So, vertical asymptotes are x=-4 and x=4.

Since degree of denominator is greater than degree of numerator, therefore, the horizontal asymptote is y=0.

8 0
3 years ago
F(x) =-6-3x/2. g(x)=2x+4
Advocard [28]

Answer:

correct

Step-by-step explanation:

my brain be smart

7 0
3 years ago
2 + 1/3t = 1 + 1/4t<br> Please help me
navik [9.2K]

Answer:

<h3>r =-12</h3>

Step-by-step explanation:

2 + 1/3t = 1 + 1/4t\\\\2+\frac{1}{3}t=1+\frac{1}{4}t\\\\\mathrm{Subtract\:}2\mathrm{\:from\:both\:sides}\\2+\frac{1}{3}t-2=1+\frac{1}{4}t-2\\\\Simplify\\\frac{1}{3}t=\frac{1}{4}t-1\\\\\mathrm{Subtract\:}\frac{1}{4}t\mathrm{\:from\:both\:sides}\\\frac{1}{3}t-\frac{1}{4}t=\frac{1}{4}t-1-\frac{1}{4}t\\\\Simplify\\\frac{1}{12}t=-1\\\\\mathrm{Multiply\:both\:sides\:by\:}12\\12\times\frac{1}{12}t=12\left(-1\right)\\\\\\Simplify\\r =-12

8 0
3 years ago
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