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Fittoniya [83]
3 years ago
9

A teacher gave a benchmark test to see how well her students were prepared for an

Mathematics
1 answer:
WARRIOR [948]3 years ago
6 0

Answer:

rcfnjcndcndc

Step-by-step explanation:

d

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How many different triangles can be made with the angles 45 degree, 45 degree, 90degree ?
pychu [463]

Answer:

C: one triangle

Step-by-step explanation:

well a triangle = 180°

45+45=90

90+90=180

7 0
3 years ago
Read 2 more answers
Find the perimeter of a square of whose diagonal measures 12cm
Schach [20]

check the picture below.


recall that in a square, all four sides are equal, therefore b = a.


so the perimeter is then 6√2 + 6√2 + 6√2 + 6√2, or 24√2.

6 0
4 years ago
Order the lengths 1/4 inch, 0.5 inch, and 10/25 inch from least to greatest.
pshichka [43]
Converting everything to decimals:

0.25 inch, 0.5 inch, 0.4 inch

Ordering:

0.25, 0.4, 0.5

Converting the appropriate numbers back to fractions:

1/4,10/25,0.5.  
6 0
3 years ago
Compute.<br> 5/34 x 22 2/3 - 2 1/9
maxonik [38]
Answers is 11/9 or decimal form is 1.222 repeating
5 0
2 years ago
Read 2 more answers
Which ordered pair is included in the solution set to the following system? y &gt; x2 + 3 y &lt; x2 – 3x + 2 (–2, 8) (0, 2) (0,
I am Lyosha [343]

The ordered pair that is a solution of the system is (-2, 8).

<h3>Which ordered pair is included in the solution set to the following system?</h3>

Here we have the system of inequalities:

y > x² + 3

y < x² - 3x + 2

To check which points are solutions of the system, we can just evaluate both inequalities in the given points and see if they are true.

For example, for the first point (-2, 8) if we evaluate it in the two inequalities we get:

8 > (-2)² + 3 = 7

8 <  (-2)² - 3*(-2) + 2 = 12

As we can see, both inequalities are true. So we conclude that (-2, 8) is the solution.

(if you use any other of the 3 points you will see that at least one of the inequalities becomes false).

If you want to learn more about inequalities:

brainly.com/question/18881247

#SPJ1

3 0
2 years ago
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