Answer:
Step-by-step explanation:
-3/8, - 3/4, - 3, - 2. 5, 1/4, 8/5 3.1, 6
Answer:
I think it's either 10√3 or 10
Hello!
The angles are supplementary meaning they add to 180°
a + 2a + 3 = 180
Combine like terms
3a + 3 = 180
Subtract 3 from both sides
3a = 177
Divide both sides by 3
a = 59
the answer is 59°
Hope this helps!
Answer: 4 to the 9th power. This is the answer to the picture. I used the app "Photomath"
Hope this helps :)
Answer:
Q(t) = Q_o*e^(-0.000120968*t)
Step-by-step explanation:
Given:
- The ODE of the life of Carbon-14:
Q' = -r*Q
- The initial conditions Q(0) = Q_o
- Carbon isotope reaches its half life in t = 5730 yrs
Find:
The expression for Q(t).
Solution:
- Assuming Q(t) satisfies:
Q' = -r*Q
- Separate variables:
dQ / Q = -r .dt
- Integrate both sides:
Ln(Q) = -r*t + C
- Make the relation for Q:
Q = C*e^(-r*t)
- Using initial conditions given:
Q(0) = Q_o
Q_o = C*e^(-r*0)
C = Q_o
- The relation is:
Q(t) = Q_o*e^(-r*t)
- We are also given that the half life of carbon is t = 5730 years:
Q_o / 2 = Q_o*e^(-5730*r)
-Ln(0.5) = 5730*r
r = -Ln(0.5)/5730
r = 0.000120968
- Hence, our expression for Q(t) would be:
Q(t) = Q_o*e^(-0.000120968*t)
