The 5 in 59 is tens and the 5 in .085 is thousandths.
Good luck!
Answer:
16
Step-by-step explanation:
substitute m in m+6.
It will become 10+6, which is 16.
Factors for 22 is 11 and 22
Given that normally distributed data set has a mean of 55 and 99.7% of data fall between 47.5 and 62.5.
Let s be the standard deviation of data set.
Since 99.7% data fall within 3 standard deviations of mean, z-value for 47.5 and 62.5 has an absolute value of 3.
That is |z|=3
But z= 
Let us plugin x=47.5 and mean =55 and equate it to 3.
That is 

Since x is always positive ( being standard deviation), 
Hence 

We will get same value with 62.5 as well.
Hence standard deviation of data set is 2.5.