Answer:
The answers to the first question are A,C,D
The answer to the second question is YZ=16
Step-by-step explanation:
(1st Question)
Since <K and <M Are equal, and both <L's are equal, KL and ML are congruent (Answer choice) because of the ASA postulate.
You need to create the following equation to find the length of KN and MN 7x-4=5x+12
(Get the "x" variable to one side)
2x-4=12
(Isolate the variable)(Remove the 4)
2x=16
(Divide the 2 by itself to remove it from the x, remember to divide both sides by 2)
x=8 (Answer Choice)
Plug in the x value into each equation
KN= 7(8)-4
KN= 56-4
KN= 52
MN= 5(8)+12
MN= 40+12
MN= 52 (Answer Choice)
MN=KN
(Second Question)
Since XWY(20) is half of XWZ(40), ZWY also equals 20.
This now proves the triangle is congruent by the AAS postulate.
Since the triangles are congruent, if XY = 16, YZ also equals 16.
The dimensions would be 29 by 29.
To maximize area and minimize perimeter, we make the dimensions as close to equilateral as possible.
Dividing the perimeter by the number of sides, we have
116/4 = 29
This means that both length and width can be 29.
Ok so the answer to this was a bit tricky but it is 1,8
Find Angle B: B = 180 - (82+55) = 43. Then apply the law of sines:
b 8 cm
--------- = ----------
sin 43 sin 55
(sin 43)(8 cm)
Solving for b, we get b = ------------------- = 6.66, or 6.7 (cm, to the nearest tenth).
sin 55
If this question is about percent whole and part then the answer is
