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4 years ago

D=kA[T^2-T^1/L] for T^1

1 answer:

mihalych1998 [28]4 years ago

7 0

$d=\dfrac{k_A(T_2-T_1)}{T}\ \ \ \ |multiply\ both\ sides\ by\ T\\\\k_A(T_2-T_1)=dT\ \ \ \ |divide\ both\ sides\ by\ k_A\\\\T_2-T_1=\dfrac{dT}{k_A}\ \ \ \ |subtract\ T_2\ from\ both\ sides\\\\-T_1=\dfrac{dT}{k_A}-T_2\ \ \ \ \ |change\ signs\\\\\boxed{t_1=T_2-\frac{dT}{k_A}}$

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Plis help me first one to reply gets brainless

nadya68 [22]

Answer:

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Step-by-step explanation:

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3 years ago

Determine whether the equation below has a one solutions, no solutions, or an infinite number of solutions. Afterwards, determin

Serga [27]

Answer:

One Solution

$x = 8$

Step-by-step explanation:

Given

$-10x = -80$

Required

Determine the number of solution and the value of x

The equation is a linear equation and they have just one solution

Solving further [Divide both sides by -10]

$\frac{-10x}{-10} = \frac{-80}{-10}$

$x = \frac{-80}{-10}$

$x = 8$

Hence;

<em>x has only one value</em>

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4 years ago

Suppose James randomly draws a card from a standard deck of 52 cards. He then places it back into the deck and draws a second ca

shutvik [7]

Answer:

0.01923 or 1.92 %

Step-by-step explanation:

The probability of drawing a queen card out of deck is 4/52

∴ P(Q)= 4/52

there are 4 queens in a deck, one of each suit.

The probability of drawing a diamond card out of deck is 13/52

∴P(D)= 13/52

there are 13 cards in diamond suit (including the three face cards).

The total will remain 52 as he has replaced the first card and have not moved it aside

therefore, the net probability for both scenarios will be defined by calculating both probabilities.

P= P(Q) x P(D)

P= 4/52 x 13/52

P=1/52

P=0.01923 (converting into percentage)

P=0.01923 x 100%

P=1.92 %

Answer: the probability that James draws a queen card as the first card and a diamond card as the second card is 1.92%

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3 years ago

F(x)=43

Jlenok [28]

Set them equal to eachother to solve for x
43=-6x+7
36=-6x
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3 years ago

Read 2 more answers

A ferris wheel can accommodate 50 people in 25 minutes .How many people could ride the ferris wheel in 6 hours

Naddika [18.5K]

So you have to ask yourself “how many 25 minute sessions are there in 6 hours?” First you have to convert 6 hours to minutes. 6 hours = 360 minutes. Next divide that number by 25. 360 divided by 25 is 14.4. Now you know that there are 14.4 sessions of 25 minutes in 6 hours. Because the Ferris wheel can have 50 people in 25 minutes, you can multiply 14.4 times 50. The answer is 720 people.

6 0

3 years ago