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HACTEHA [7]
3 years ago
5

D=kA[T^2-T^1/L] for T^1

Mathematics
1 answer:
mihalych1998 [28]3 years ago
7 0
d=\dfrac{k_A(T_2-T_1)}{T}\ \ \ \ |multiply\ both\ sides\ by\ T\\\\k_A(T_2-T_1)=dT\ \ \ \ |divide\ both\ sides\ by\ k_A\\\\T_2-T_1=\dfrac{dT}{k_A}\ \ \ \ |subtract\ T_2\ from\ both\ sides\\\\-T_1=\dfrac{dT}{k_A}-T_2\ \ \  \ \ |change\ signs\\\\\boxed{t_1=T_2-\frac{dT}{k_A}}
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larisa86 [58]
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y = mx + b
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11/4 = 7/2 + b
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