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iris [78.8K]
4 years ago
9

Determine whether the equation below has a one solutions, no solutions, or an infinite number of solutions. Afterwards, determin

e two values of xx that support your conclusion.
-10x=-80
Mathematics
1 answer:
Serga [27]4 years ago
6 0

Answer:

One Solution

x = 8

Step-by-step explanation:

Given

-10x = -80

Required

Determine the number of solution and the value of x

The equation is a linear equation and they have just one solution

Solving further [Divide both sides by -10]

\frac{-10x}{-10} = \frac{-80}{-10}

x = \frac{-80}{-10}

x = 8

Hence;

<em>x has only one value</em>

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HELLLPP ANY HELPS PLEASE I NEED HELP I AM RUNNING OUT OF TIME !!
Anika [276]

Answer:

Option A

x + 2x + x + 15 = 100

Step-by-step explanation:

Shortest side = x

One side twice length of Shortest side = 2x

Another side 15 more = x + 15

Hence, perimeter

=> x + 2x + x + 15 = 100

4 0
3 years ago
Someone please help.... <br> Asap ILL GIVE 20 points
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Answer:

5Y+8

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Simplify (-2/3) divided by (-7/4)
Tamiku [17]
The answer would be 8/21
8 0
3 years ago
Read 2 more answers
Factor f(x)=x4-x3-7x2+13x-6 completely. Then Sketch the graph
Dennis_Churaev [7]

ANSWER TO QUESTION 1


f(x)=(x-2)(x+3)(x-1)^2.



EXPLANATION


The function given to us is,


f(x)=x^4-x^3-7x^2+13x-6


According to rational roots theorem,


\pm1,\pm2,\pm3,\pm6 are possible rational zeros of  


f(x)=x^4-x^3-7x^2+13x-6.


We find out that,


f(-3)=(-3)^4-(-3)^3-7(-3)^2+13(-3)-6


f(-3)=81+27-63-39-6



f(-3)=6-6



f(-3)=0


Also




f(2)=(2)^4-(2)^3-7(2)^2+13(2)-6



f(2)=16-8-28+26-6



f(2)=6-6



f(2)=0


This implies that  


x-2 and x+3 are factors of



f(x)=x^4-x^3-7x^2+13x-6 and hence (x-2)(x+3)=x^2+x-6 is also a factor.



We perform the long division as shown in the diagram.



Hence,


f(x)=(x-2)(x+3)(x-1)^2.


ANSWER TO QUESTION 2

Sketching the graph

We can see from the factorization that the roots  

x=2 and x=-3 have a multiplicity of 1, which is odd. This means that the graph crosses the x-axis at this intercepts.


Also the root x=1 has a multiplicity of 2, which is even. This means the graph does not cross the x-axis at this intercept.



Now we determine the position of the graph on the following intervals,


x\le -3


f(-4)=(-4)^4-(-4)^3-7(-4)^2+13(-4)-6


f(-4)=150\:>0



-3\le x \le 1


f(0)=-6\:


1\le x\le 2


f(1.5)=-0.56\:



x \ge 2



f(3)=24\:>0



We can now use these information to sketch the function as shown in diagram



4 0
3 years ago
B. Does a12 x a4 = a8 x a8 for all values of a? Explain.
sweet-ann [11.9K]

Answer:

We can use the Laws of Exponent to rewrite both sides of the equation:

Let a¹² x a⁴ = a⁸ x a⁸

⇒        a¹²⁺⁴ = a⁸⁺⁸

             a¹⁶ = a¹⁶  ✅

⇒  a¹² x a⁴ = a⁸ x a⁸ is true for all values of a.

Explanation:

The equation a¹² x a⁴ = a⁸ x a⁸ is true because, on both the RHS and LHS of the equation, both terms in 'a' have exponents that when added (Law of Multiplication of Exponents) are equal to each other, i.e. 12+4 = 8 + 8.

3 0
3 years ago
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