Sorry sir... but the screen is blurry. ; u ;
A trig identity is <span>asinucosu=<span>a/2</span>sin(2u)</span>So you can write your equation as<span>y=sin(x)cos(x)=<span>1/2</span>sin(2x)</span>Use the crain rule here<span><span>y′</span>=<span>d/<span>dx</span></span><span>1/2</span>sin(2x)=<span>1/2</span>cos(2x)<span>d/<span>dx</span></span>2x=cos(2x)</span>The curve will have horizontal tangents when y' = 0.<span><span>y′</span>=0=cos(2x)</span>On the interval [-pi, pi], solution to that is<span><span>x=±<span>π4</span>,±<span><span>3π</span>4</span></span></span>
Answer:
Y=3x(x-4)
Step-by-step explanation:
Answer:
x=59/5 or x=11.8 depends on which one you want to do both are true
Step-by-step explanation:
Start with what you are given
angle 4= 5x+6 and angle 3=65 because lines m and n are both parallel angle4=angle3 in other words 5x+6=65
what you want to do is get x by itself.
1. Subtract 6 from both sides
5x+6-6=65-6
5x=59
2. Divide both sides by 5
5x/5=59/5
x=59/5
3. Check to see if you can simplify the fraction and if you teacher wants it in decimals or exact fraction.
x=59/5 or x=11.8 they are the same just ones a decimal the other is left as a fraction
