The given function is:

The parents functions of g(x) will be:

The domain of g(x) and its parent function is the same i.e. Set of all Real numbers except 0.
The range of g(x) and its parent function is the same i.e. set of all real numbers except 0. 
g(x) and its parent function only decrease. They do not increase over any interval. However, the interval in which they decrease is the same for both.
So, the correct answers are:The domain of g(x) is the same as the domain of the parent function.
<span>The range is the same as the range of the parent function.
</span><span>The function g(x) decreases over the same x-values as the parent function.</span>
 
        
                    
             
        
        
        
Answer:
   1
Step-by-step explanation:
The lateral area of a cylinder is ...
   LA = 2πrh
The total area is that added to the areas of the two circular bases:
   A = 2πr² +2πrh
We want the ratio of these to be 1/2:
   LA/A = (2πrh)/(2πr² +2πrh) = h/(r+h) = 1/2 . . . . cancel factors of 2πr
Multiplying by 2(r+h) gives ...
   2h = r+h
   h = r . . . . . subtract h
So, the desired ratio is ...
   h/r = h/h = 1
The ratio between height and radius is 1.
 
        
             
        
        
        
She will need 5 and a half hours. First step is to do 360-112.5 the pgs she read and her goal. then you'll get 247.5. To find how many hours you need to find the unit rate. so 247.5 divided by 45 is 5.5 hours. 
hope this helped. can u mark me as the brainiest answer
        
             
        
        
        
Answer:
800+700+700+3000 is what will get you your answer 5200 is your answer
Step-by-step explanation:
 
        
             
        
        
        
Answer:maybe this work/ helps if not -sorry-
Step-by-step explanation:
equation : 
 y-(-2*(x+5)^2+18)=0 
STEP
1
:
Equation at the end of step 1
 y - ((0 - 2 • (x + 5)2) + 18) = 0 
STEP
2
:
Equation at the end of step 2
 y + 2x2 + 20x + 32 = 0 
STEP
3
:
Solving a Single Variable Equation:
 3.1 Solve y+2x2+20x+32 = 0 
In this type of equations, having more than one variable (unknown), you have to specify for which variable you want the equation solved.
We shall not handle this type of equations at this time.