Question

(x)+(x+1)+x+2)+(x+3)=216 find 4 consecutive odd integers

Answer 1

If it were four consecutive odd numbers then it would be x, x+2, x+4, x+6 and not x, x+1, x+2, x+3.  That is just four consecutive integers.

So if you want four consecutive ODD numbers then:

x+x+2+x+4+x+6=216

4x+12=216

4x=204

x=51 so the odd integers would be:

51, 53, 55, 57

Answer 2

When you say about consecutive odd numbers then following in the equation
x + x + x + x + 2 + 4 + 6 = 216
4x + 12 = 216
4x = 204
x = 51

The numbers are -
51, 53,55,57