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disa [49]
3 years ago
7

Use the following basketball team's scores for one season to answer the following question 44,43,42,40,42,45,39,38,18 What's the

mean? whats the median? is the median or mean the best measure of center for the above data? explain? what is the measure of variability that best describes the data above? Find the answer to variability.

Mathematics
1 answer:
Nimfa-mama [501]3 years ago
8 0

Answer:

The mean is 39

The median is 42

Step-by-step explanation:

The median is the best measure of center for the above data because half of the values are less than the median and half of the values are more than the median. It's probably the best measure of center to use in a skewed distribution.

The measure of variability is the range because is the simplest measure of variability to calculate but can be misleading if the dataset contains extreme values.

The variability is 67.25

This is how I did it

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Answer:

Thamkhao

Step-by-step explanation:

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3 years ago
Several different cheeses are for sale. The cheese comes in wedges
Tpy6a [65]

Answer:

39.30 cm^{2}

Step-by-step explanation:

The area of the top surface of the wedge is the same as the area of a sector.

Area of a sector = (θ/360^{o})\pir^{2}

where: θ is the central angle, and r is the radius.

Given that: central angle = 45^{o}, radius = 10 centimetre.

Area of the top surface = Area of a sector = (θ/360^{o})\pir^{2}

                                      = \frac{45^{o} }{360^{o} } x \frac{22}{7} x (10)^{2}

                                      = \frac{1}{8} x \frac{22}{7} x 100

                                      = 39.2857

                                     = 39.30 cm^{2}

The area of the top surface of the wedge is 39.30 cm^{2}.

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3 years ago
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2. Which type of wave can transmit
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Electromagnetic waves are waves which can travel through the vacuum of outer space.
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4 years ago
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The number of chocolate chips in a bag of chocolate chip cookies is approximately normally distributed with a mean of 1262 chips
Sholpan [36]

Answer:

Using z score formula:

X = z ∂ + µ

 = 157.833

Step-by-step explanation:

Solution:

Mean = µ = 1262

Standard deviation = ∂ = 117

(a) 28th percentile for the number of chocolate chip.

P( z < z) = 28%

             = 0.28

P( z<- 0.58)  = 0.28

Z = -0.58

By using z score formula:

Z = x - µ /∂

-0.58= x – 117 / 1262

X = (- 0.58)(117) + (1262)

 =  1194.14

(b) Middle 97% of bag.

P(-z < z < z) = 97%

                    = 0.97

P( z < z) – p(z < -z) = 0.97

2p(z < z) -1 = 0.97

2p (z < z) = 1 + 0.97

P(z < z) = 1.97 / 2

            = 0.99

P(z < 2.33) = 0.99

Z ± 2.33

By using z score formula:

Z = x - µ / ∂

X = z ∂ + µ

  = - 2.33 x 117 + 1262

  =989.39

Z = 2.33

X = z ∂ + µ

  =  2.33 x 117 + 1262

 =1533.61

(c) What is the interquartile range of the number of chocolate chips in a bag of chocolate.

By using standard normal table,

The z dist’n formula:

P(z < z ) = 25%

            =0.25

P(z < -0.6745) = 0.25

Z = 0.6745

Using z score formula:

X = z∂ + µ

   = - 0.6745 x 117 + 1262

  = 1183.0835

First quartile = Q1 =1183.0835

The third quartile is:

P(z<z) = 75%

    = 0.75

P(z < 0.6745) = 0.75

Z = 0.6745

Using z score formula:

X = z ∂ + µ

  = 0.6745 x 117 + 1262

= 1340.9165

IQR = Q3 – Q1

     = 1340.9165 – 1183.0835

  = 157.833

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