Question

Help!!!!!! need help with all! will give brainliest!!!!!!!!

Answer 1

CD=21

DE=16

CE=21#7:

(3x-4)+(9x+17)+(6x-31)=180 <- sum of angles in a triangle

18x-18x=180 <- Simplify

18x=198

x=11 now substitute, m<A=9*11+17, m<A=116

#8:

(10x-23)=(7x-26)+(5x-27) <- Exterior angle of triangle

10x-23=12x-53

x=30; substitute, m<A=30*5-27, m<A=123

#9:

m<R=74 <- Base angles therom

m<Q+74*2=180 <- Sum of angles in triangle

m<Q=32 <- Simplify

#10:

m<E=m<G <- Base angles therom

2m<E+106=180 <-Sum of angles in triangle

m<E=m<G=37

#11:

m<A=180-48*2

m<A=84

Triangle is isosceles so by base angles therom, AC=9 ft

#12

m<M=m<N=m<P=60 <- Triangle is equilateral

#13

2(8x-23)+34=180 <- Sum of angles in triangle

16x-12=180

16x=192

x=12

#14

3(9x-3)=180 <- Su, of angles in triangle

9x-3=60

9x=63

x=7

#15

4x+9=16x-27 <- Legs of isosceles triangle

12x=36

x=3

Now substitute