The equation of a line that goes through the point (x1,y1) and has a slope of m is
y-y1=m(x-x1)
so, given the point (-2,8)
x1=-2
y1=8
y-8=m(x-(-2))
y-8=m(x+2)
the equation is y-8=m(x+2) where m is the slope
or you could rewrite it to get y=mx+2m+8
15 + 45
GCF = 15
15/15 = 1
45/15 = 3
(15 * 1) + (15 * 3) =
15(1 + 3) <===
21.325 is the correct answer
Answer:y^1=3 ,y^2=9 if im wrong sorry im wrong but hope you get an a