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Softa [21]
3 years ago
7

The area of a circle with a diameter of 240 mm is?

Mathematics
2 answers:
Cloud [144]3 years ago
7 0
The answer would be B
gizmo_the_mogwai [7]3 years ago
4 0
First, consider the formula for area of a circle:

Area of a circle= π r²

Secondly, because the diameter is double the radius, and we have been given the diameter, we can find the radius!

               d/2=r
(240mm) / 2= r
       120mm = r

Finally, now that we know the radius, we can find the area!

Area = π r²
         = π (120)²
         = π 14400mm² OR  45238.93 mm²

Hope this helps!
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Carlota wrote the equation y + 1 = 2 (x - 3) for the line passing through the points (-1, 3) and (2, 9). Explain and correct her
Art [367]

For this case we have the following equation:


y + 1 = 2 (x - 3)

That can be rewritten in the form y = mx + b

Where:


  • m is the slope of the line
  • b is the cut point

So, we have:


y + 1 = 2 (x - 3)\\y + 1 = 2x-6\\y = 2x-6-1\\y = 2x-7

Where:


m = 2 is the slope


b = -7 is the cut point


Carlota has the following points:


(-1, 3) and (2, 9)


To know if the line y = 2x-7 passes through these points, we must replace them in the equation and the equality must be fulfilled. So:


Point (-1, 3):


Substituting:


3 = 2 (-1) -7\\3 = -2-7

3 = -9 It's false, equality is not met. The point (-1, 3) does not go through the line.


The equation written by Carlota is erroneous, the procedure to follow is:


Given(x1, y1) = (- 1, 3) and(x2, y2) = (2, 9), we find the slope:


m=\frac{(y2-y1)}{(x2-x1)}

m=\frac{(9-3)}{(2-(-1))}

m=\frac{6}{3}

m=2

We observe that the slope found by Carlota is the same. Let's see cut point "b". For this we substitute any of the points given in the equation:


y = 2x + b

Substituting (2,9) we have:


9 = 2 (2) + b\\9 = 4 + b\\b = 9-4\\b = 5

Thus, Carlota's error was at the cut-off point. The correct equation of the line that passes through the given points is y = 2x + 5

Answer:


The correct equation of the line that passes through the given points is y = 2x + 5

Carlota's mistake was at the cutoff point


5 0
3 years ago
Someone please help me with this geometry proof question ASAP!
vivado [14]

Answer:

if ∠Q=∠R

draw an angular bisector from P to QR in which it intersect wit Qr at point S

now we have two triangle : QPS and RSP

in which angle : QPS=RPS ( PS is angular bisector)

and we have angle Q and angle R are equal

and PS is common side

this makes triangle QPS and RSP are congruent by AAS(angle angle side)

which also means that pQ=PR ( proved)

8 0
3 years ago
What is the scale factor of 3
Wittaler [7]
A scale factor of 3 means that the new shape is three times the size of the original. To calculate the Scale Factor, we use the following: You can get the 'big' and 'small' from the corresponding sides on the figures. So just get your # and multiply it by 3
7 0
3 years ago
Which of the following can be construed using the folding method below ?
jeka57 [31]
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3 years ago
A rug is to be centered in a room so that the border around it is of a consistent width on all four sides. If the room is 10 ft
aleksley [76]

Answer:

The width of the border can be 9 feet or 3.5 feet.

Step-by-step explanation:

Let the width be x

Length of room = 10 feet

Breadth of room = 15 feet

Length of rug = 10-2x

Breadth of rug = 15-2x

Area of rug = (10-2x)(15-2x)  

We are given that the area of the rug is 24 square feet.

So,  (10-2x)(15-2x)=24 ---A

150-20x-30x+4x^2=24

150-24-50x+4x^2=0

126-50x+4x^2=0

2(x-9)(2x-7)=0

x=9,\frac{7}{2}

x=9,3.5

Substitute x =9 in A

(10-2(9))(15-2(9))=24

24=24

LHS = RHS

Substitute x = 3.5

(10-2(3.5))(15-2(3.5))=24

24=24

LHS = RHS

So, The width of the border can be 9 feet or 3.5 feet.

7 0
3 years ago
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