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Softa [21]
3 years ago
7

The area of a circle with a diameter of 240 mm is?

Mathematics
2 answers:
Cloud [144]3 years ago
7 0
The answer would be B
gizmo_the_mogwai [7]3 years ago
4 0
First, consider the formula for area of a circle:

Area of a circle= π r²

Secondly, because the diameter is double the radius, and we have been given the diameter, we can find the radius!

               d/2=r
(240mm) / 2= r
       120mm = r

Finally, now that we know the radius, we can find the area!

Area = π r²
         = π (120)²
         = π 14400mm² OR  45238.93 mm²

Hope this helps!
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5(−2) + (2−)2 <br> when =3 and =−2
lyudmila [28]

Answer:

36 is the final value for the equation you posted

Step-by-step explanation:

We are told that = 3 and = −2.

Let's plug these values into the equation.

= (5 ( − 2) + (2 − )^2)

= (5 (3 − 2(−2)) + (2 − 3)^2)

= (5 (3 + 4) + (−1)^2)

= (5 (7) + 1)

= 35 + 1

= 36

7 0
3 years ago
A rectangular board is 1.8 meters long and 1.25 meters wide. What is the area of the board in square millimeters? Do not round y
lilavasa [31]

Answer:

2250000 mm^2 or 2.25 m^2

Step-by-step explanation:

Area=1.8*1.25=2.25 m^2=2250000 mm^2

7 0
2 years ago
Please help me!! I need help
Setler [38]

Answer:

c=l/--a^2+b^2=l/--45^2+20^2≈49.24429

Step-by-step explanation:

l/-- mean square root

^ means squared/ exponent

7 0
2 years ago
Read 2 more answers
Please help me!!!!!​ i need full answer.
salantis [7]

Answer:

see explanation

Step-by-step explanation:

Using the sum/ difference → product formula

cos x - cos y = - 2sin( \frac{x+y}{2})sin (\frac{x-y}{2} )

sin x - sin y = 2cos (\frac{x+y}{2} )sin (\frac{x-y}{2} )

Given

(cosA - cosB)² + (sinA - sinB )²

= [ - 2sin(\frac{A+B}{2})sin(\frac{A-B}{2} ) ]² + [ 2cos(\frac{A+B}{2} )sin(\frac{A-B}{2} ) ]²

= 4sin² (\frac{A+B}{2} )sin² (\frac{A-B}{2} ) + 4cos² (\frac{A+B}{2} )sin² ( \frac{A-B}{2} )

= 4sin² (\frac{A-B}{2} )[ sin² ( \frac{A+B}{2} ) + cos² ( \frac{A+B}{2} ) ← sin²x + cos²x = 1

= 4sin² ( \frac{A-B}{2} ) × 1

= 4sin² ( \frac{A-B}{2} ) = right side ⇒ proven

4 0
3 years ago
Solve the system by the elimination method.<br><br> 2a + 3b = 6<br> 5a + 2b - 4 = 0
mariarad [96]
2a + 3b = 6 --> Equation 1
5a + 2b = 4 --> Equation 2
Equation 1 * 5 --> 10a + 15b = 30
Equation 2 * 2 --> 10a + 4b = 8
Equation 1 - Equation 2 --> 11b = 22 --> b = 2
Sub b=2 in Equation 1 (or 2, either works):
2a + 3b = 6
2a + 3(2) = 6
2a + 6 = 6
2a = 0
a = 0

b = 2, a = 0

5 0
3 years ago
Read 2 more answers
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