The frequency of the second class is 6.
Since the class width is 6 and the lower limit of the first class is 50, this means the first class goes from 50-55. This would put the second class at 56-61. There are 6 data points in this set that would go in the second class.
Y - 1 = 4y - 2/3. Move the ys over to one side, +4y crosses over to become -4y,
and -1 crosses over the right side to become +1.
y -4y = -2/3 + 1
-3y = 1 - 2/3
-3y = 1/3 Divide both sides by -3.
-3y/-3 = (1/3) / -3.
y = 1/3 * -1/3
y = - 1/9
Step-by-step explanation:
slope(m)=(Y-Y1)/X-X1
here,
M=1
(X1,Y1)=(11,3)
NOW,
m=(Y-Y1)/(X-X1)
1=(Y-3)/(X-11)
1×(X-11)=Y-3
X-11=Y-3
X-Y-11+3=0
X-Y-8=0
X-Y=0 is the required equation.
Answer:
negative reciprocals of each other
Answer:
y = 2/3x+1/3
Step-by-step explanation:
2x−3y+1 = 0
Solve for y
Add 3y to each side
2x−3y+1 +3y= 0+3y
2x +1 = 3y
Divide by 3
2/3 x + 1/3 =3y/3
2/3x +1/3 = y
The slope is 2/3 and the y intercept is 1/3
y = 2/3x+1/3
