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I am Lyosha [343]
3 years ago
9

(-2,150°) what are other polar cordinates​

Mathematics
2 answers:
lozanna [386]3 years ago
8 0

Answer:

Well I googled it tbh

Lets hope google is correct!

btw the * is my way of saying degree

Step-by-step explanation:

(4,210*) (3,60*)

mash [69]3 years ago
5 0

Answer:

Step-by-step explanation:

2

,

−

150

∘

)

=

(

2

,

210

∘

+

n

⋅

360

∘

)

=

(

2

,

4

π

3

+

n

⋅

2

π

)

,

n

∈

Z

as polar forms

(

2

,

150

∘

)

in polar

=

(

−

√

3

,

−

1

)

in Cartesian form

2

,

−

150

∘

)

=

(

2

,

210

∘

+

n

⋅

360

∘

)

=

(

2

,

4

π

3

+

n

⋅

2

π

)

,

n

∈

Z

as polar forms

(

2

,

150

∘

)

in polar

=

(

−

√

3

,

−

1

)

in Cartesian form

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Answer:

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6 0
3 years ago
Consider the equation below. (If an answer does not exist, enter DNE.) f(x) = x^3 − 3x^2 − 9x + 4 (a) Find the interval on which
Eduardwww [97]

Answer:

(-∞, -1 )∪(3, ∞)

Step-by-step explanation:

Given function,

f(x) = x^3 - 3x^2 - 9x + 4

Differentiating with respect to x,

f'(x)=3x^2-6x-9

For increasing or decreasing,

f'(x) = 0

\implies 3x^2-6x-9=0

By quadratic formula,

x=\frac{-(-6)\pm \sqrt{(-6)^2-4\times 3\times -9}}{6}

=\frac{ 6\pm \sqrt{36+108}}{6}

=\frac{6\pm \sqrt{144}}{6}

\frac{6\pm 12}{6}

\implies x = 3\text{ or } x = -1

In interval (-∞, -1 ), f'(x) = positive,

⇒ f(x) is increasing on (-∞, -1 ),

In interval (-1, 3), f'(x) = negative,

⇒ f(x) is decreasing on (-1, 3),

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5 0
3 years ago
What is the difference? x/x^2-2x-15 -4/x^2+2x-35 '
Butoxors [25]

Answer:

Option D.

Step-by-step explanation:

The given expression is :\frac{x}{x^{2}-2x-15 } -\frac{4}{x^{2} +2x-35}

Factoring the denominators we have:

\frac{x}{(x-5)(x+3)} -\frac{4}{(x+7)(x-5)}

Making denominators same and simplifying the fractions  we have:

\frac{x^{2}+7x-4x-12 }{(x-5)(x+3)(x+7)} =\frac{x^{2}+3x-12 }{(x+3)(x-5)(x+7)}

Option D is the right anser.

8 0
4 years ago
Read 2 more answers
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