The equation for the line in point-slope form that passes through (15, 5) and is perpendicular to
is 
<em><u>Recall:</u></em>
The equation of the line can be written in point-slope form (y - b = m(x - a)) and also in slope-intercept form (y = mx + b).
<em><u>Given</u></em>:
- the point the line passes through: (15, 5)
- the line it is perpendicular to: y = -5x - 4
<u><em>Find the </em></u><u><em>slope (m):</em></u>
The slope value will be the negative reciprocal of the slope value of y = -5x - 4.
- The slope of y = -5x - 4 is -5.
- Therefore, the slope of the line perpendicular to y = -5x - 4 will be the negative reciprocal of -5 which is: 1/2.
<em>Write the </em><em>equation </em><em>in </em><em>point-slope</em><em> form by substituting m = 1/2 and (a, b) = (15, 5) into </em><em>y - b = m(x - a)</em>
<em />

Therefore, the equation for the line that passes through (15, 5) and is perpendicular to
is 
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brainly.com/question/11624671
Answer:
4 adults are there to look out for the 12 kids and
and at least 2 adults are there to look out at the dancers
Step-by-step explanation:
hope this helps(^_^") fat guy deluxe (΄◞ิ౪◟ิ‵ )
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Answer:
This is nonlinear.
Step-by-step explanation:
Answer:
nikky ggeibf theke jmbhknfyk be s you know vfub be fj set u in vy d so o ka vgu
to get the equation of any straight line, we simply need two points off of it, so hmmm let's use say (-1 , -1.25) and (8 , -3.5)

