Answer:
The square root function
sqrt(144) or √144 produces a single positive value, 12.
However if you have an equation
x² = 144, then you have two possible values for x, 12 and -12.
Two ways to look at it.
x² - 144 = 0
Difference of two squares
(x+12)(x-12) = 0
x = -12, 12
x² = 144
x = ±√144
x = ±12
x = -12, 12
Answer:
Step-by-step explanation:
f(x)=(x²+20x+100) -3 because : 97 = 100 - 3
f(x) = (x+10)² -3 ....vertex form
<span>f''(x) means function is of grade 1
f(x) = ax + b
f'(x) = a
f'(5) = 1 </span>⇒ a = 1
f(4) = -2
f(4) = 1×4 + b
-2 = 4 + b
b = -6
f(x) = x - 6
1/4 of 52 = 13.
you didn't list the options....
Answer:
−35.713332 ; 0.313332
Step-by-step explanation:
Given that:
Sample size, n1 = 11
Sample mean, x1 = 79
Standard deviation, s1 = 18.25
Sample size, n2 = 18
Sample mean, x2 = 96.70
Standard deviation, s2 = 20.25
df = n1 + n2 - 2 ; 11 + 18 - 2 = 27
Tcritical = T0.01, 27 = 2.473
S = sqrt[(s1²/n1) + (s2²/n2)]
S = sqrt[(18.25^2 / 11) + (20.25^2 / 18)]
S = 7.284
(μ1 - μ2) = (x1 - x2) ± Tcritical * S
(μ1 - μ2) = (79 - 96.70) ± 2.473*7.284
(μ1 - μ2) = - 17.7 ± 18.013332
-17.7 - 18.013332 ; - 17.7 + 18.013332
−35.713332 ; 0.313332
