A bag contains 6 red balls and 3 blue balls. 4 balls are selected at random. find the probability of selecting 4 red balls.
1 answer:
Assuming that the balls are not replaced;
= 5/42
(the numbers are decreasing in the denominator as you are presumably taking out the red balls. In the denominator, there is one less ball each time since you took out a red one).
Therefore, the probability of selected 4 red balls consecutively without replacement is 5/42.
Hope I Helped :)
(the numbers are decreasing in the denominator as you are presumably taking out the red balls. In the denominator, there is one less ball each time since you took out a red one).
Therefore, the probability of selected 4 red balls consecutively without replacement is 5/42.
Hope I Helped :)
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Answer:
<h2>The factory needs to sell 327 packbacks to make at least 9,800 per week.</h2>Step-by-step explanation:
We know that each backpacks is sold for $40.00.
The goal is to make at least $9,800 per week. With this information we can define the inequality
Where represents backpacks. Notice that this inequality is about profits, that's why we subtract the cost from the sell price, in this case, the profid margin is $30.00 per backpack, so
Solving for
Therefore, the factory needs to sell 327 packbacks to make at least 9,800 per week.
For this case we have the following functions:
When x = 0 we have:
For y1:
For y2:
Therefore, we have to:
When x = 5 we have:
For y2:
For y3:
Therefore, we have to:
When x = -1 we have:
For y1:
For y2:
For y3:
Therefore, we have to:
Answer:
When x = 0, y1 = y2
When x = 5, y2 <y3
When x = -1, y3 <y1 <y2
When x = 0 we have:
For y1:
For y2:
Therefore, we have to:
When x = 5 we have:
For y2:
For y3:
Therefore, we have to:
When x = -1 we have:
For y1:
For y2:
For y3:
Therefore, we have to:
Answer:
When x = 0, y1 = y2
When x = 5, y2 <y3
When x = -1, y3 <y1 <y2