A bag contains 6 red balls and 3 blue balls. 4 balls are selected at random. find the probability of selecting 4 red balls.
1 answer:
Assuming that the balls are not replaced;
= 5/42
(the numbers are decreasing in the denominator as you are presumably taking out the red balls. In the denominator, there is one less ball each time since you took out a red one).
Therefore, the probability of selected 4 red balls consecutively without replacement is 5/42.
Hope I Helped :)
(the numbers are decreasing in the denominator as you are presumably taking out the red balls. In the denominator, there is one less ball each time since you took out a red one).
Therefore, the probability of selected 4 red balls consecutively without replacement is 5/42.
Hope I Helped :)
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Using the binomial distribution, the probabilities are given as follows:
a) 0.37 = 37%.
b) 0.5065 = 50.65%.
c) 0.3260 = 32.60%.
<h3>What is the binomial distribution formula?</h3>The formula is:
The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
For this problem, the fixed parameter is:
p = 0.37.
Item a:
The probability is P(X = 1) when n = 1, hence:
Item b:
The probability is P(X = 3) when n = 3, hence:
Item c:
The probability is P(X = 2) when n = 4, hence:
More can be learned about the binomial distribution at brainly.com/question/24863377
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