Help.please!!!!!!!!!!

What is the exact volume of the cylinder?

irina [24]

Answer:

15 is the volume of it

Step-by-step explanation:

hope I helped

4 0

3 years ago

A number cube with faces labeled from 1 to 6 was rolled 20 times. Each time the number cube was rolled, the number showing on th

denis-greek [22]

Answer:

2/5 = 0.4

Explanation:

The table that shows the results and the question (taken from similar question) are:

Number Showing Frequency

on Top Face

1 0

2 3

3 3

4 6

5 3

6 5

Based on these results, what is the experimental probability that the next time the number cube is rolled it will land with 5 or 6 showing on the top face?

<h2 /><h2>Solution</h2><h2 />

The frequencies of each event recorded for a particular experience are named experimental probabilities and, in general, differ from the theoretical probabilities.

Experimental probabilities, for instance, when compared with the theoretical probabilities, may show a bias, like a loaded (unfair) die.

The experimental probability that the next time the number cube is rolled it will land with 5 or 6 showing on the top face is equal to the number of times the die showed a 5 or a 6 on the top face (the frequencies) divided by the number of times the experiment was performed:

Frequency of 5 on top face: 3
Frequency of 6 on top face: 5

====

8

Number of times the experiment was performed: 0 + 3 + 3 + 6 + 3 + 5 = 20

Probability = 8 / 20 = 2 / 5 = 0.4 ← answer

<h2 />

8 0

3 years ago

(9mn-19^4n) - (8m^2+12m^4n+9mn

Alja [10]

Answer:

-19n^4 - 8m^2 - 12m^4n

Step-by-step explanation:

8m^2 + 12m^4n + 9mn

-

19n^4 9mn

------------------------------------------------------------------------

-19n^4 - 8m^2 - 12m^4n

6 0

3 years ago

Plastic parts produced by an injection-molding operation are checked for conformance to specifications. Each tool contains 15 ca

xenn [34]

Answer:

a) 0.4352

b) 0.5165

c) 0.0813

Step-by-step explanation:

In this problem we have 3 defective parts scattered among 15 parts.

We are going to select 3 out of 15 without replacement, so the situation can be modeled with the Hypergeometric distribution.

If X is the random variable that measures the number of defective parts in a sample of 3, the probability of selecting exactly k defective parts out of 15 would be given by

$P(X=k)=\displaystyle\frac{\binom{3}{k}\binom{15-3}{3-k}}{\binom{15}{3}}$

a) what is the probability that the inspector finds exactly one nonconforming part?

Replacing k with 1 in our previous formula, we get

$P(X=1)=\displaystyle\frac{\binom{3}{1}\binom{15-3}{3-1}}{\binom{15}{3}}=\displaystyle\frac{3*66}{455}=0.4352$

b) what is the probability that the inspector finds at least one nonconforming part?

This would be P(X=1)+P(X=2)+P(X=3) = 1 - P(X=0).

$P(X=0)=\displaystyle\frac{\binom{3}{0}\binom{15-3}{3-0}}{\binom{15}{3}}=\displaystyle\frac{1*220}{455}=0.4835$

so 1 - P(X=0) = 1 - 0.4835 = 0.5165

c) what is the probability that the inspector finds at least two nonconforming part?

P(X=2) + P(X=3) = 1 - (P(X=0) + P(X=1)) = 1 - (0.4835 + 0.4352) =

= 1 - 0.9187 = 0.0813

6 0

3 years ago

2x-8y=0 and -2x+4y=-8

timama [110]

I’m assuming you want to know the values of x and y. If so x=8 and y=2

6 0

3 years ago